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我与具有验证关联的对象有标准的 has_many 关系。但我不知道如何避免错误堆栈级别太深。

这是我的两个模型

class Address < ActiveRecord::Base
 belongs_to :employee, :inverse_of => :addresses
end

class Employee < ActiveRecord::Base

  has_many :addresses, :dependent => :destroy, :inverse_of => :employee     #inverse of       can use addresses.employee
  has_many :typings
  has_many :types, through: :typings

  validates :addresses, length: { minimum: 1 }
  validates :types, length: { minimum: 1 }


end

这里是我的工厂

FactoryGirl.define do
 factory :address, class: Address do
   address_line 'test'
   name 'Principal'
   city 'test'
   zip_code 'test'
   country 'france'
 end
end

FactoryGirl.define do
 factory :employee_with_address_type, class: Employee do |e|
   e.firstname   'Jeremy'
   e.lastname    'Pinhel'
   e.nationality 'France'
   e.promo       '2013'
   e.num_mobile  'Test'
   e.types { |t| [t.association(:type)] }
   after :build do |em|
    em.addresses << FactoryGirl.build(:address)
   end
 end
end

这是我的模型测试

describe Address do
  context 'valid address' do
  let(:address) {FactoryGirl.build(:address)}
  subject {address}

  #before(:all) do
  #  @employee = FactoryGirl.build(:employee_with_address_type)
  #end

  it 'presence of all attributes' do
     should be_valid
  end
 end
end

有人可以帮我理解如何解决这个问题吗？我尝试与我的工厂进行不同的组合，但没有成功。

编辑：

 class Employee < ActiveRecord::Base

  has_many :addresses, :dependent => :destroy, :inverse_of => :employee     #inverse of       can use addresses.employee
  has_many :typings
  has_many :types, through: :typings

  validates_associated :addresses
  validates_associated :types


 end
4

1 回答 1

0

您可以按如下方式重写您的工厂：

     FactoryGirl.define do
      factory :address_with_employee, class: Address do
        address_line 'test'
        name 'Principal'
        city 'test'
        zip_code 'test'
        country 'france'
        association :employee, :factory => :employee_with_address_type
        after :build do |ad|
          ad.employee.addresses << ad
        end
      end
     end

     FactoryGirl.define do
      factory :employee_with_address_type, class: Employee do |e|
        e.firstname   'Jeremy'
        e.lastname    'Pinhel'
        e.nationality 'France'
        e.promo       '2013'
        e.num_mobile  'Test'
        e.types { |t| [t.association(:type)] }
      end
     end

我所做的只是将创建的地址实例直接添加到其员工地址中。在这个构建后循环中，您当然也可以为同一员工创建其他地址并将它们添加到列表中。

于 2013-08-05T10:09:21.613 回答