linux - 根据 CSV 输入选择和压缩文件

Question

我正在尝试读取 csv 文件中的每一列，然后使用 csv 列中的数据搜索目录。读取完所有行后，我想创建一个新目录，将文件复制到该目录，最后压缩该目录。关于如何做的任何想法？

以下是 CSV 文件的示例：

add an example here...

Answer 1

我不知道，如果您想以不同的方式处理每一列，但如果没关系，这里有一个脚本的草稿。

separator=";" # select separator type in your csv file
csv_file="`pwd`/file.csv" # path to your csv file
search_dir="`pwd`/searchdir" # directory, where we search for files, that are in csv files
copy_to_dir="`pwd`/newdir" #directory where to save copied files

mkdir $copy_to_dir #making copy dir

for i in `cat ${csv_file} | tr $separator '\n'` ; do # reading all the entries in csv file    
    find $search_dir -name "$i" | xargs -i cp {} $copy_to_dir
    # assuming, that all entries in csv are files to be found in a dir and copied     
done

zip -j -r copied_files.zip $copy_to_dir # zip found contents
rmdir $copy_to_dir # if you need just the zip file

Answer 2

This is a draft of the script based on the informations you gave:

destdir="/path/to/destination/directory"
filelist=""
while IFS=, read col1 col2 col3 col4 ...
do 
  # check if the file should be included in filelist
  if [ ... ]; then
    filelist+="$col1/$col2/$col3.$col4 "
  fi

  if [ ! -z "$filelist" ]; then
    mkdir -p $destdir
    for goodfile in $filelist; do
      cp $goodfile $destdir
    done
  fi
done < file.csv

To make things clearer I assumed the columns in the CSV file are just the parts of the path and name of the files you're interested in. Hope this helps. :)