我在几个网站上搜索了我的问题，但我无法得到它。我正在寻找的是如何在响应返回成功删除行的消息后刷新页面。我的页面 admin2.php 显示来自 DB 的管理员信息以及学生表（来自 DB），该表在学生的每一行旁边都有一个复选框。我通过 Ajax 发送表单（表格）以转到（admin3Response.php）页面进行检查，然后返回响应。这是我的代码有问题。
admin2.php
<tr><th>Admin Information</th>
<th style="width: 212px"></th></tr>
<tr><td><b>Admin Name: <?php echo $name; ?></b><span name="adminName"></span></td>
<td style="width: 212px"><b>Admin ID: <?php echo $userID; ?></b><span name="adminID"></span></td></tr>
<tr><td><b>Phone: <?php echo $phone; ?></b><span name="adminPhone"></span></td>
<td style="width: 212px"><span></span></td></tr>
admin2.php 这是我想要刷新的表单。从此表中，我可以选择要删除的学生。
else if(isset($dropStudent))
{
if(mysql_num_rows($QueryResult7) == 0)
{
?>
<h2><?php echo ("There are no students available.");?></h2>
<p>
<div class="form_settings">
<input class="submit" type="button" onclick="goBack()" name="delete0" value="Back" style="margin-left: 0px; width: 89px">
</div>
<?php
}
else
{
?>
<form name="form3" id ="form3" method="" action="admin2.php" >
<input type="hidden" value="Delete" name="deleteStudent">
<?php
echo $adminUser;
?>
<TABLE style="width:100%; border-spacing:1;">
<TR><TH>Choose</TH><TH>USER_ID</TH><TH>STUDENT NAME</TH><TH>EMAIL</TH><TH>PHONE</TH> <TH>MAJOR</TH><TH>GPA</TH><TH>DEGREE</TH></TR>
<?php
$Row7 = mysql_fetch_row($QueryResult7);
// reads row of query into indexed array
// advances result pointer
do
{
echo '<TR><TD><input type="checkbox" name="checkbox[]" value="' . $Row7[0] . '"></TD>' .
"<TD>{$Row7[0]}</TD>
<TD>{$Row7[1]}</TD>" .
"<TD>{$Row7[2]}</TD>
<TD>{$Row7[3]}</TD>" .
"<TD>{$Row7[4]}</TD>
<TD>{$Row7[5]}</TD>" .
"<TD>{$Row7[6]}</TD>
</TR>";
$Row7 = mysql_fetch_row($QueryResult7);
} while ($Row7); // tests for content of null
?>
<input type="hidden" value="<?php echo $countStds; ?>" name="countStds">
<input type="hidden" value="<?php echo $adminUser; ?>" name="adminUser">
<tr>
<td colspan="10">
</tr>
<?php
mysql_close($DBConnect);
?>
</TABLE>
</form>
<script>
// $("#form3") grabs the above form with an ID of "form3"
$("#form3").on('submit', function(){
// Grab all form values
var values = $("#form3").serialize();
// Send form values over ajax
$.ajax({
method: 'POST',
url: 'admin3Response.php',
data: values,
// execute when response comes back from admin3Response.php
success: function(data){
// data = whatever admin3Response echo'd back
// check for success
if (data.lastIndexOf("success") >= 0) {
// no errors
alert("Student was dropped successfully");
window.location.reload(true); // It reload an empty page; didn't work
//alert("TODO: redirect user somewhere?");
} else {
// Display error message
alert(data);
}
}
})
return false;
});
</script>
<?php
}
}
admin3Response.php
else if(isset($deleteStudent))
{
if (isset($checkbox))
{
for($i=0; $i<$countStds; $i++)
{
$delStudent = $checkbox[$i];
$wholeStudents = mysql_query("DELETE USERS, ENROLLMENTS, OVERIDES FROM USERS, ENROLLMENTS, OVERIDES WHERE USERS.USER_ID = ENROLLMENTS.USER_ID AND ENROLLMENTS.USER_ID = OVERIDES.USER_ID AND USERS.USER_ID = '$delStudent'");
$delUserStudent = mysql_query("DELETE USERS FROM USERS WHERE USER_ID = '$delStudent'");
$delOverStudent = mysql_query("DELETE OVERIDES, USERS FROM OVERIDES, USERS WHERE USERS.USER_ID = OVERIDES.USER_ID AND USERS.USER_ID = '$delStudent'");
$delEnrStudent = mysql_query("DELETE ENROLLMENTS, USERS FROM ENROLLMENTS, USERS WHERE USERS.USER_ID = ENROLLMENTS.USER_ID AND USERS.USER_ID = '$delStudent'");
}
echo ("You have deleted "); echo count($checkbox); echo (" student(s) `enter code here`successfully.");
echo ("success");
}
else
{
echo ("No student selected");
}
mysql_close($DBConnect);
}
我尝试使用“window.location.reload(true);”，但它重新加载了一个空页面。我的猜测是我需要使用 get 方法将所有变量从 admin3Response.php 传递给 admin2.php 但我不知道该怎么做。任何帮助将不胜感激。