regex - 使用 shell 脚本格式化文本文件内容

Question

事情是我想使用 shell script 格式化我的文本文件内容。内容是这样的：

http://copyright.gov.in Inlinks:
 fromUrl: http://mhrd.gov.in/ anchor: Copyright
 fromUrl: http://mhrd.gov.in/hi/home anchor: कॉपीराइट
 fromUrl: http://mhrd.gov.in/?fontsize=normal anchor: Copyright
 fromUrl: http://mhrd.gov.in/?contrast=high anchor: Copyright
 fromUrl: http://mhrd.gov.in/?fontsize=large anchor: Copyright
 fromUrl: http://mhrd.gov.in/sitemap anchor: Copyright
 fromUrl: http://mhrd.gov.in/?fontsize=small anchor: Copyright
 fromUrl: http://mhrd.gov.in/hi anchor: कॉपीराइट
 fromUrl: http://mhrd.gov.in/?contrast=normal anchor: Copyright

我希望格式化输出为：

http://copyright.gov.in -> http://mhrd.gov.in/
http://copyright.gov.in -> http://mhrd.gov.in/hi/home 
http://copyright.gov.in -> http://mhrd.gov.in/?fontsize=normal

等等

Answer 1

$ cat foo.input
http://copyright.gov.in Inlinks:
 fromUrl: http://mhrd.gov.in/ anchor: foo
 fromUrl: http://mhrd.gov.in/hi anchor: bar
http://foo.acme.gov Inlinks:
 fromUrl: http://foo.acme.gov/ anchor: foo
 fromUrl: http://foo.acme.gov/about anchor: bar

 

$ awk '/^http/ { host=$1; next } NF { printf "%s -> %s\n", host, $2 }' foo.input
http://copyright.gov.in -> http://mhrd.gov.in/
http://copyright.gov.in -> http://mhrd.gov.in/hi
http://foo.acme.gov -> http://foo.acme.gov/
http://foo.acme.gov -> http://foo.acme.gov/about