6

我刚刚开始阅读 JavaScript,我正在尝试编写一个小的递归函数,该函数将搜索给定的节点并将值列表作为字符串返回。

我的 HTML 结构可能类似于

<div id="parentfolder">parentfolder1
    <div class ="item1">item1</div>
    <div class ="item2">item2</div>
    <div id="parentfolder">parentfolder2
        <div class ="item1">item1</div>
        <div class ="item2">item2</div>
    </div>
</div>

这是我的 Javascript 函数:

function jsoncreator(parentfolderclass){
    var jstring = '';

    //get first occurance of parent folder
    var parentfolder = document.getElementById(parentfolderclass);
    var childnodes = parentfolder.childNodes;

    for (property in childnodes){
        jstring += property+ childnodes[property];
        if(childnodes[property] === parentfolderclass){
            jsoncreator(parentfolderclass);
            jstring += childnodes[property].value + '<br>';
        }
        else{
            //jstring += childnodes[i].value + '<br>';
        }
    }
    document.write(jstring);
}

我回来的只是

0[object Text]1[object HTMLDivElement]2[object Text]3[object HTMLDivElement]4[object Text]5[object HTMLDivElement]6[object Text]length7itemfunction item() { [native code] }

当我尝试打印子节点值时,我得到一堆未定义的返回。

如果有人能解释我做错了什么,我将不胜感激。

4

2 回答 2

10

您将需要执行以下操作(递归跨浏览器)

Javascript

function walkTheDOM(node, func) {
    func(node);
    node = node.firstChild;
    while (node) {
        walkTheDOM(node, func);
        node = node.nextSibling;
    }
}

function textNodeValuesToArray(node) {
    if (typeof node === "string") {
        node = document.getElementById(node);
    }

    var arrayOfText = [];

    function pushText(currentNode) {
        if (currentNode.nodeType === 3) {
            arrayOfText.push(currentNode.nodeValue);
        }
    }

    walkTheDOM(node, pushText);

    return arrayOfText;
}

console.log(textNodeValuesToArray("parentfolder"));

jsfiddle 上

或使用treewalker

浏览器兼容性

支持 IE9+、FF2+、Chrome 1+、Safari 3+、Opera 9+

Javascript

function textNodeValuesToArray(node) {
    if (typeof node === "string") {
        node = document.getElementById(node);
    }

    var arrayOfText = [],
        treeWalker = document.createTreeWalker(node, NodeFilter.SHOW_TEXT, {
            acceptNode: function (node) {
                return NodeFilter.FILTER_ACCEPT;
            }
        }, false);

    while (treeWalker.nextNode()) {
        arrayOfText.push(treeWalker.currentNode.nodeValue);
    }

    return arrayOfText;
}

console.log(textNodeValuesToArray("parentfolder"));

jsfiddle 上

没有递归和跨浏览器将是这样的

Javascript

避免使用标签

标签在 JavaScript 中不是很常用,因为它们使程序更难阅读和理解。尽可能避免使用标签,并且根据具体情况,更喜欢调用函数或抛出错误。

function walkDOM(root, func) {
    var node = root;

    start: while (node) {
        func(node);
        if (node.firstChild) {
            node = node.firstChild;
            continue start;
        }

        while (node) {
            if (node === root) {
                break start;
            }

            if (node.nextSibling) {
                node = node.nextSibling;
                continue start;
            }

            node = node.parentNode;
        }
    }
}

function textNodeValuesToArray(node) {
    if (typeof node === "string") {
        node = document.getElementById(node);
    }

    var arrayOfText = [];

    function pushText(currentNode) {
        if (currentNode.nodeType === 3) {
            arrayOfText.push(currentNode.nodeValue);
        }
    }

    walkDOM(node, pushText);

    return arrayOfText;
}

console.log(textNodeValuesToArray("parentfolder"));

jsfiddle 上

于 2013-08-01T21:40:58.767 回答
1
<div id="parentfolder">parentfolder1
  <div class ="item1">item1</div>
  <div class ="item2">item2</div>
  <div class="subfolder">parentfolder2
    <div class ="item1">item1</div>
    <div class ="item2">item2</div>
  </div>
</div>



var children = document.getElementById('parentfolder').getElementsByClassName('*');
var childValues = new Array();

for(i=0; i<children.length; i++) {
  if(children[i].className == 'subfolder') {
    continue;
  } else {
    childValues.push(children[i].innerHTML);
  }
}
于 2013-08-01T21:15:18.027 回答