我想创建一个字典作为带有链接列表的哈希表来拼写检查文本文档。我读入文件“words.txt”来创建字典。此外,当我在字典“words.txt”中加载时,我必须计算/显示哈希表中每个插槽的冲突次数
我得到了带有链表的 HashTable 类的源代码,如下所示:
hashtable.cpp (#include "listtools.cpp" 因为它使用模板)
#include <iostream>
#include <string>
#include "listtools.h"
#include "listtools.cpp"
#include "hashtable.h"
using LinkedListSavitch::Node;
using LinkedListSavitch::search;
using LinkedListSavitch::headInsert;
using namespace std;
#define HASH_WEIGHT 31
namespace HashTableSavitch
{
HashTable::HashTable()
{
for (int i = 0; i < SIZE; i++)
{
hashArray[i] = NULL;
//array for collisons
collisionArray[i] = 0;
}
}
HashTable::~HashTable()
{
for (int i=0; i<SIZE; i++)
{
Node<string> *next = hashArray[i];
while (next != NULL)
{
Node<string> *discard = next;
next = next->getLink( );
delete discard;
}
}
}
unsigned int HashTable::computeHash(string s) const
{
unsigned int hash = 0;
for (unsigned int i = 0; i < s.length( ); i++)
{
hash = HASH_WEIGHT * hash + s[i];
}
return hash % SIZE;
}
bool HashTable::containsString(string target) const
{
int hash = this->computeHash(target);
Node<string>* result = search(hashArray[hash], target);
if (result == NULL)
return false;
else
return true;
}
void HashTable::put(string s)
{
int count = 0;
int hash = computeHash(s);
if (search(hashArray[hash], s) == NULL)
{
// Only add the target if it's not in the list
headInsert(hashArray[hash], s);
}
else
{
collisionArray[hash]++;
}
void HashTable::printArray()
{
int number;
for(int i = 0; i < SIZE; i++)
{
number = collisionArray[i];
cout << "----------------\n";
cout << "index = " << i << endl;
cout << "Collisions = " << number << endl;
cout << "----------------\n";
}
}
} // HashTableSavitch
我的 main.cpp 文件
#include <iostream>
#include <fstream>
#include <cctype>
#include <algorithm>
#include <cstring>
#include <string>
#include "hashtable.h"
using namespace std;
using HashTableSavitch::HashTable;
void upToLow(string & str);
void removePunct(string & str);
int main()
{
HashTable h;
string currWord;
string word;
int countMisspelled = 0;
int countCorrect = 0;
//Get input from words.rtf
ifstream dictionary("words.txt");
//File checking
if (dictionary.fail())
{
cout << "File does not exist" << endl;
cout << "Exit program" << endl;
}
//Create the dictionary as a hash table
while(dictionary >> currWord)
{
h.put(currWord);
}
dictionary.close();
//display collisions
h.printArray();
//Get input from gettysburg_address.txt
ifstream input("gettysburg_address.txt");
//File checking
if (input.fail())
{
cout << "File does not exist" << endl;
cout << "Exit program" << endl;
}
//Spell check gettysburg_address.txt
cout << "Misspelled words : " << endl;
cout << endl;
//If a word is not in the dictionary assume misspelled
while(input >> word)
{
removePunct(word);
upToLow(word);
if(h.containsString(word) == false)
{
countMisspelled++; // Increment misspelled words count
cout << word << " ";
if(countMisspelled % 20 == 0) // Display misspelled words 20 per line
{
cout << endl;
}
}
else
{
countCorrect++; // Increment correct words count
}
}
input.close();
cout << endl;
cout << endl;
cout << "Number of misspelled words : " << countMisspelled << endl;
cout << "Number of correct words : " << countCorrect << endl;
return 0;
}
/*Function to convert uppercase letters to lowercase*/
void upToLow(string & str)
{
for (unsigned int i = 0; i < strlen(str.c_str()); i++)
if (str[i] >= 0x41 && str[i] <= 0x5A)
str[i] = str[i] + 0x20;
}
/*Function to remove punctuation from string*/
void removePunct(string & str)
{
str.erase(remove_if(str.begin(), str.end(), static_cast<int(*)(int)>(&ispunct)),str.end());
}
加载“words.txt”时,是否有一种简单的方法来计算每个插槽的冲突次数?如果我在“put”函数中实现一个计数变量,我可以获得冲突的总数,但我不太确定如何计算/显示哈希表每个槽的冲突数。任何帮助/提示表示赞赏。
编辑:听从乔的建议,现在我想知道如何显示每个插槽的碰撞次数。我做了一个 void 函数来做到这一点,但它显示每个插槽的碰撞次数为 0。有人知道我应该做什么吗?