我正在尝试通过命令行使用 7 Zip。如下所示,使用该命令会7z l
列出目标 zip 文件中的 3 个文件。
C:\Users\User1\Downloads>7z l recording_20130731180507.zip
--
Path = recording_20130731180507.zip
Type = zip
Physical Size = 311686
Date Time Attr Size Compressed Name
------------------- ----- ------------ ------------ ------------------------
2013-07-31 18:05:06 ..... 655 655 SD_DISK\20130731\18\2013073
1_180505_A4BC_00408CC2B40B\recording.xml
2013-07-31 18:05:06 ..... 309752 309752 SD_DISK\20130731\18\2013073
1_180505_A4BC_00408CC2B40B\20130731_18\20130731_180505_59EB_00408CC2B40B.mkv
2013-07-31 18:05:06 ..... 279 279 SD_DISK\20130731\18\2013073
1_180505_A4BC_00408CC2B40B\20130731_18\20130731_180505_59EB_00408CC2B40B.xml
------------------- ----- ------------ ------------ ------------------------
310686 310686 3 files, 0 folders
但是,当我尝试实际解压缩文件时,我收到“没有要处理的文件错误”。我以前从未尝试过从 cmd 解压缩。我是否必须尝试挖掘 zip 文件来提取这 3 个文件?
C:\Users\User1\Downloads>7z e recording_20130731180507.zip o-C:\users\User1\do
cuments\folder1\test
No files to process
Files: 0
Size: 0
Compressed: 311686