1

我的表有三列[ID], [YEAR], [MALES]，对于任何给定的 ID，在多个 YEAR 值上可以有多个 MALES 值。

前任。

[ID]     [YEAR]     [MALES]
1        2010       10
1        2011       20
1        2011       35
1        2011       0
1        2012       25
1        2012       10
2        2010       5
2        2011       2
2        2011       11
2        2011       12
2        2012       0
2        2012       10

我需要为每个 ID 查询该 YEAR 的最大 YEAR 和最大 MALES 值。所以上面例子的结果是：

[ID]     [YEAR]     [MALES]
1        2012       25
2        2012       10
4

4 回答 4

2

您想使用以下方法执行此操作row_number()：

select id, year, males
from (select t.*,
             row_number() over (partition by id
                                order by years desc, males desc
                               ) as seqnum
      from t
     ) t
where seqnum = 1;
于 2013-08-01T18:02:48.717 回答
0

您需要使用子查询来获取最大年份，然后加入该查询以获取该年份的最大 MALES。

SELECT  T.ID
        ,SQ.MAX_YEAR
        ,MAX(T.MALES)
FROM    TABLE1 T
INNER JOIN
        (
        SELECT  ID
                ,MAX(YEAR) AS MAX_YEAR
        FROM    TABLE1 
        GROUP BY
                ID
        ) SQ
ON      T.ID = SQ.ID
AND     T.YEAR = SQ.MAX_YEAR
GROUP BY
        T.ID
        ,SQ.MAX_YEAR
于 2013-08-01T18:03:46.203 回答
0

如果我明白你想要什么（你的措辞有些困难，但这个例子看起来你想要我的第二个）。

每个 ID 的最长年份：

SELECT id, MAX(year) FROM data;

最大年份的每个 ID 的最大男性数量：

SELECT id, year, MAX(males) FROM data WHERE year = (SELECT MAX(year) FROM data) 
    GROUP BY id;
于 2013-08-01T18:04:35.357 回答
0 
;with CTE as
(
    select
        *,
        row_number() over (partition by ID order by year desc, males desc) as row_num
    from table
)
select *
from CTE
where row_num = 1

或者

;with CTE as
(
    select ID, max(Year) as Year
    from table
    group by ID
)
select t.ID, t.Year, max(males) as males
from table as t
    inner join CTE as c on c.ID = t.ID and c.Year = t.Year
group by t.ID, t.year
于 2013-08-01T18:00:21.500 回答