3

您能否更简单地在另一个标签（“数据”）中反序列化 XML（“项目”）而不在“项目”获取属性中使用另一个反序列化。也许是“public Item[] Items”上的某种属性。

XML:

<body>
  <request></request>
  <data><![CDATA[
    <items>
      <item>
        <property1>Name1</property1>
        <property2>111</property2>
      </item>
      <item>
        <property1>Name2</property1>
        <property2>222</property2>
      </item>
      <item>
        <property1>Name3</property1>
        <property2>333</property2>
      </item>
    </items>]]>
  </data>
</body>

测试类：

    [TestClass]
    public class UnitTest1
    {
        [TestMethod]
        public void TestMethod1()
        {
            const string xml = "<body>" +
                                    "<request></request>" +
                                    "<data><![CDATA[" +
                                        "<items>" +
                                            "<item>" +
                                                "<property1>Name1</property1>" +
                                                "<property2>111</property2>" +
                                            "</item>" +
                                            "<item>" +
                                                "<property1>Name2</property1>" +
                                                "<property2>222</property2>" +
                                            "</item>" +
                                            "<item>" +
                                                "<property1>Name3</property1>" +
                                                "<property2>333</property2>" +
                                            "</item>" +
                                        "</items>" +
                                    "]]></data>" +
                               "</body>";

            var xmlDoc = new XmlDocument();
            xmlDoc.LoadXml(xml);

            var serializer = new XmlSerializer(typeof (Body));
            var response = serializer.Deserialize(new XmlNodeReader(xmlDoc)) as Body;

            Assert.IsNotNull(response);
            Assert.AreEqual(3, response.Items.Length);
        }
    }

    [Serializable, XmlRoot("body")]
    public class Body
    {
        [XmlElement("request")] 
        public string Request;

        [XmlElement("data")] 
        public string Data;

        public Item[] Items
        {
            get
            {
                var document = new XmlDocument();
                document.LoadXml(Data);

                var serializer = new XmlSerializer(typeof(ItemList));
                var response = serializer.Deserialize(new XmlNodeReader(document)) as ItemList;

                return response.Items;
            }
        }
    }

    [Serializable, XmlRoot("items")]
    public class ItemList
    {
        [XmlElement("item")]
        public Item[] Items;
    }

    [Serializable]
    public class Item
    {
        [XmlElement("property1")]
        public string Property1;

        [XmlElement("property2")]
        public string Property2;
    }
4

1 回答 1

0

在反序列化 XML 之前，将 XML 加载到 XmlDocument 并更改“数据”XmlNode InnerXml，如下所示：

if (xmlNode.Contains("<![CDATA[") || xmlNode.InnerXml.Contains("&lt;"))
{
     xmlNode.InnerXml = xmlNode.Value;
}

如果您知道您将在 CDATA 中收到什么，这将起作用。

于 2013-10-07T14:37:48.967 回答