我正在尝试在 C# .NET 中编写 SOAP 消息(包括标头)以使用 HTTP 发布发送到 URL。我想将它发送到的 URL 不是 Web 服务,它只是接收 SOAP 消息以最终从中提取信息。关于如何做到这一点的任何想法?
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9336 次
2 回答
15
首先,您需要创建一个有效的 XML。我使用 Linq to XML 来实现这一点,如下所示:
XNamespace soapenv = "http://schemas.xmlsoap.org/soap/envelope/";
var document = new XDocument(
new XDeclaration("1.0", "utf-8", String.Empty),
new XElement(soapenv + "Envelope",
new XAttribute(XNamespace.Xmlns + "soapenv", soapenv),
new XElement(soapenv + "Header",
new XElement(soapenv + "AnyOptionalHeader",
new XAttribute("AnyOptionalAttribute", "false"),
)
),
new XElement(soapenv + "Body",
new XElement(soapenv + "MyMethodName",
new XAttribute("AnyAttributeOrElement", "Whatever")
)
)
);
然后我使用(编辑:XDocument.ToString()
在此处添加。)
var req = WebRequest.Create(uri);
req.Timeout = 300000; //timeout
req.Method = "POST";
req.ContentType = "text/xml;charset=UTF-8";
using (var writer = new StreamWriter(req.GetRequestStream()))
{
writer.WriteLine(document.ToString());
writer.Close();
}
如果我必须阅读一些回复,我会这样做(这是上述代码的后续):
using (var rsp = req.GetResponse())
{
req.GetRequestStream().Close();
if (rsp != null)
{
using (var answerReader =
new StreamReader(rsp.GetResponseStream()))
{
var readString = answerReader.ReadToEnd();
//do whatever you want with it
}
}
}
于 2009-11-25T18:41:36.670 回答
0
您上面的代码缺少括号并且有一个额外的逗号,我在这里修复了它:
XNamespace soapenv = "http://schemas.xmlsoap.org/soap/envelope/";
var document = new XDocument(
new XDeclaration("1.0", "utf-8", String.Empty),
new XElement(soapenv + "Envelope",
new XAttribute(XNamespace.Xmlns + "soapenv", soapenv),
new XElement(soapenv + "Header",
new XElement(soapenv + "AnyOptionalHeader",
new XAttribute("AnyOptionalAttribute", "false")
)
),
new XElement(soapenv + "Body",
new XElement(soapenv + "MyMethodName",
new XAttribute("AnyAttributeOrElement", "Whatever")
)
)
)
);
于 2012-04-10T14:32:54.323 回答