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我有一个数据集，我需要过滤“唯一”事件。基本上，我想删除同一用户一天内多次购买同一产品的每一行，而不管可变设备如何。在多次出现的情况下，我只保留第一行。

数据：

datetime, device, product, user

  [
  ['2013-07-08 15:00:00', 'pc',       'X',        'A'],
  ['2013-07-09 17:00:00', 'pc',       'X',        'A'],
  ['2013-07-09 10:00:00', 'andr',     'Y',        'B'],
  ['2013-07-10 18:00:00', 'pc',       'Y',        'B'],
  ['2013-07-10 21:00:00', 'ipho',     'Y',        'B'],       <- second occurance of B getting Y that day
  ['2013-07-10 22:00:00', 'andr',     'Y',        'B'],       <- third occurance of B getting Y that day
  ['2013-07-10 02:00:00', 'ipho',     'Z',        'C'],
  ['2013-07-10 11:00:00', 'pc',       'Z',        'C']        <- second occurance of C getting Z that day
  ]

应该过滤到：

  ['2013-07-08 15:00:00', 'pc',       'X',        'A'],
  ['2013-07-09 17:00:00', 'pc',       'X',        'A'],
  ['2013-07-09 10:00:00', 'andr',     'Y',        'B'],
  ['2013-07-10 18:00:00', 'pc',       'Y',        'B'],
  ['2013-07-10 02:00:00', 'ipho',     'Z',        'C'],
  ['2013-07-10 11:00:00', 'pc',       'Z',        'C']

我该怎么做呢？

4

1 回答 1

4

从日期时间中去除时间部分，然后将每个项目存储在字典中，如果它不存在的话。作为字典的键，使用日期、产品、用户的元组。

例如

 d = {}
 for datetime, device, product, user in table:
     date = datetime[:10]
     if (date, product, user) not in d:
         d[(date, product, user)] = [datetime, device, product, user]
于 2013-08-01T08:46:16.500 回答