1

我有以下查询，它从新闻文章表中选择。由于多种排序因素，我无法找到下一页的日期。

我的参数是查询结果集中的最后一个 ID，那么如何获取下一页...再次，我没有页面索引，我只有上一个查询结果集中的最后一个 ID

SELECT TOP (20) ID, 
                Datediff(SECOND, CONVERT(DATETIME, '1970-01-01', 102), 
                RELEASE_DATE) AS date, 
                Datediff(SECOND, CONVERT(DATETIME, '1970-01-01', 102), EDIT_DATE 
                )    AS lastchanged, 
                IMPORTANT 
FROM   ARTICLES AS news WITH (NOLOCK) 
WHERE  ( STATUS = 1 ) 
       AND ( RELEASE_DATE <= Getutcdate() ) 
ORDER  BY IMPORTANT DESC, 
          DATE DESC, 
          LASTCHANGED DESC

这是我的数据示例

  id       date     lastchanged important
187346  1366070400  1345212540  1
187306  1365984000  1345290300  1
187330  1365984000  1342457880  1
187344  1363392000  1342461540  1
187343  1363392000  1342461300  1
187342  1363392000  1342459980  1
187339  1363392000  1342459800  1
187337  1363392000  1342458960  1
187335  1363392000  1342458720  1
187334  1363392000  1342458600  1
187332  1363392000  1342458060  1
187331  1363392000  1342457940  1
187327  1363392000  1342457340  1
187328  1363392000  1342457340  1
187326  1363392000  1342456860  1
187323  1363392000  1342456020  1
187322  1363392000  1342455480  1
187321  1363392000  1342454700  1
187316  1363392000  1342454580  1
187320  1363392000  1342454520  1
4

2 回答 2

2

如果您想要在某个应用程序中一次显示 20 个帖子并能够获取，那么接下来的 20 个帖子直到结果结束可能使用OFFSET FETCH 子句可能会起作用。

初始查询将是：

SELECT        
    id, DATEDIFF(SECOND, CONVERT(DATETIME, '1970-01-01', 102), release_date) AS date,  DATEDIFF(SECOND, CONVERT(DATETIME, '1970-01-01', 102), edit_date) AS lastchanged, important
FROM articles AS news WITH (NOLOCK)
WHERE (status = 1) AND (release_date <= GETUTCDATE())
ORDER BY important DESC, date DESC, lastchanged DESC
OFFSET 0 ROWS FETCH NEXT 20 ROWS ONLY;

和后续查询将增加offset值：

SELECT        
    id, DATEDIFF(SECOND, CONVERT(DATETIME, '1970-01-01', 102), release_date) AS date,  DATEDIFF(SECOND, CONVERT(DATETIME, '1970-01-01', 102), edit_date) AS lastchanged, important
FROM articles AS news WITH (NOLOCK)
WHERE (status = 1) AND (release_date <= GETUTCDATE())
ORDER BY important DESC, date DESC, lastchanged DESC
OFFSET 20 ROWS FETCH NEXT 20 ROWS ONLY;
于 2013-08-01T08:14:15.910 回答
1 
;WITH CTE( ROW,ID, 
                [date], 
                [lastchanged], 
                IMPORTANT ) AS
(
SELECT rOW_NUMBER() OVER(oRDER BY IMPORTANT DESC, 
          DATE DESC, 
          LASTCHANGED DESC ) AS rOW,ID, 
                Datediff(SECOND, CONVERT(DATETIME, '1970-01-01', 102), 
                RELEASE_DATE) AS date, 
                Datediff(SECOND, CONVERT(DATETIME, '1970-01-01', 102), EDIT_DATE 
                )    AS lastchanged, 
                IMPORTANT 
FROM   ARTICLES AS news WITH (NOLOCK) 
WHERE  ( STATUS = 1 ) 
       AND ( RELEASE_DATE <= Getutcdate() ) 
                ) 

SELECT TOP 20 ID, 
                [date], 
                [lastchanged], 
                IMPORTANT FROM CTE WHERE rOW>cOALESCE((sELECT rOW FROM CTE WHERE iD=1871),0);

这是示例。在示例中，我仅选择前 5 个，因此输入任何 ID，您会看到它将获取接下来的五个记录。

Sql Fiddle Demo - 首先输入错误的 id，比如我在这里输入 -1，而不是你将获得前五条记录。

Sql Fiddle Demo - Enter id=187339 since it last id for first page

Sql Fiddle Demo - Enter id=187331 since it last id for second page 依此类推

于 2013-08-01T09:08:08.677 回答