我正在玩 Go 的openpgp包,方法是制作一个简单的程序来加密短消息并用 ASCII 保护它。我目前拥有的代码是:
package main
import (
"code.google.com/p/go.crypto/openpgp"
"code.google.com/p/go.crypto/openpgp/armor"
"fmt"
"log"
"os"
)
func main() {
to, err := openpgp.NewEntity("John Smith", "comment", "john@example.com", nil)
if err != nil {
log.Fatal(err)
}
from, err := openpgp.NewEntity("John Smith", "comment", "john@example.com", nil)
if err != nil {
log.Fatal(err)
}
recipients := []*openpgp.Entity{to}
armorer, err := armor.Encode(os.Stdout, "PGP MESSAGE", nil)
if err != nil {
log.Fatal(err)
}
defer armorer.Close()
encrypter, err := openpgp.Encrypt(armorer, recipients, from, nil, nil)
if err != nil {
log.Fatal(err)
}
defer encrypter.Close()
fmt.Fprintf(encrypter, "Hello! How are you?")
}
当我运行它时,我得到输出:
-----BEGIN PGP MESSAGE-----
wcBMA5iJWayscZQHAQgAvHQtyGxzyHJNYQlK7bcYZnWRm1gHsRRVZIgPTxtqnklp
KgCYOuv5dtgqUXinJWZnk3DozR7xbMj/c9oSlifJ9FiPnTaLLOIVhv2Jf7w9ydh3
oig3vpL8rI/ha9bOJsNdznt3/z1ZLVghPsrRGHO7LWUTWQUn/cgQZXr/z5CpGQP0
TFlMcbBuuwE2ffplAGkBSQlXNRx1ZsY6T+MjajWwcik/CjJ/NnzRpURpXFIWc85x
HQbUexQzEghyh4t5NEQhx9UvmLtnKPmwnhxX3s43Zcd1VtzSXc77giE08fSdIDdH
eDClMno6jsoWhmubXZVXOHqf+z5euEcxvYyk16N/jdLgAeMBTSifCFR8YuGBmOFA
DONO/4/M1ye76+KyhsbF4KTgK+CW4Rjg4NLi0ubP1A==
=YD2p
-----END PGP MESSAGE-----panic: crypto: requested hash function is unavailable
goroutine 1 [running]:
crypto.Hash.New(0x9, 0x21027c4b0, 0x1d3300)
/usr/local/Cellar/go/1.1.1/src/pkg/crypto/crypto.go:62 +0xab
code.google.com/p/go.crypto/openpgp.Encrypt(0x210299e70, 0x2102e76e0, 0x2210284f38, 0x1, 0x1, ...)
/Users/cb/workspace/go/src/code.google.com/p/go.crypto/openpgp/write.go:289 +0x1141
main.main()
/Users/cb/workspace/go/src/github.com/xoebus/gpg/go-gpg.go:31 +0x425
exit status 2
看起来它正在输出装甲密文(这似乎是无效的)然后崩溃,因为它找不到链接到二进制文件的注册哈希函数。据我所知,默认情况下它应该使用标准库中的一个 SHA 哈希值,它肯定应该被链接?
我究竟做错了什么?