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我已经在我的表中创建了 Jcombobox，如下所示。

代码

          TableColumn col5 = jTable1.getColumnModel().getColumn(4);      
          String[] options = new String[]{"Font Issue","Text Issue","Image Issue","AI Issue","Others"};
          JComboBox combo1 = new JComboBox(options);
          JComboBox combo2 = new JComboBox(options);
          col5.setCellEditor(new DefaultCellEditor(combo1));
          col5.setCellRenderer(new ComboBoxRenderer(combo2));
          col5.setPreferredWidth(150);
          combo2.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e) {                
                String dropDownValue = col5.getCellEditor().getCellEditorValue().toString();
                if(dropDownValue.equalsIgnoreCase("others"))
                {
                    JOptionPane.showMessageDialog(null, "alert", "alert", "");
                }
            }
        });

当我尝试获取 dropwon 值时出现错误。

错误

local variable col5 is accessed from within inner class; needs to be declared final.

我什至试过这样。

String dropDownValue = combo1.getSelectedItem().toString();

但我得到了类似的错误

local variable combo1 is accessed from within inner class; needs to be declared final

请帮忙。谢谢

4

1 回答 1

0

改变这个

 TableColumn col5 = jTable1.getColumnModel().getColumn(4);

至

 final TableColumn col5 = jTable1.getColumnModel().getColumn(4);

您正在定义一个匿名类。为了避免 java 变量中的闭包产生奇怪的副作用，必须将其标记为 final。

于 2013-08-01T03:33:57.283 回答