mysql - sql更新错误

Question

我将 2012 年参加理赔的操作员的工资提高了 11%，试试

update operator or
September o.sueldo = o.sueldo + (o.sueldo * 0.11)
where exists (select 1 from claim where r.cod_operador r = o.cod_operador
and r.fecha Between '2012-01-01 'and '2012-12-31');

但它显示“错误代码：1241。操作数应包含 1 列”有人知道我该如何解决这些错误吗？

sqlfiddle 在这里：http ://sqlfiddle.com/#!2/b2771

Answer 1

你对这个声明做了什么？

这样它至少适合你的桌子：

update operador o
set o.sueldo = o.sueldo + (o.sueldo * 0.11)
where exists (select 1 from reclamo r where r.cod_operador = o.cod_operador
and r.fecha Between '2012-01-01 'and '2012-12-31');

但我不知道它最终是否会做正确的事情......

Answer 2

我认为您的查询应该是

update operator o
SET o.sueldo = o.sueldo + (o.sueldo * 0.11)
where exists (select 1 from claim where r.cod_operador r = o.cod_operador
and r.fecha Between '2012-01-01 'and '2012-12-31');