3

我想从每个项目中提取所有客户的报价，如果他们有多个报价，我想要平均值。

我有以下查询：

SELECT
@projectid := projects.id AS projectid,
(SELECT
  SUM(`offers`) FROM
  (SELECT AVG( `price` ) AS `offers`
    FROM `sales`
    WHERE `sales`.`projectid` = @projectid
    AND `sales`.`active` = 'yes'
    GROUP BY `sales`.`clientid`
  ) AS `average`
) AS `outstanding`
FROM projects
WHERE
projects.active = 'yes'
ORDER BY outstanding ASC

我的问题是@projectid没有传递到子查询中，我不明白我应该如何解决这个问题。

谁能给我一些建议？

4

1 回答 1

0

请记住，SQL 是一种声明性语言，而不是命令性语言。许多问题可以通过使用JOIN不带“变量”的子查询来解决。所以...

......我不太确定理解 - 但你只需要“为每个项目计算每个客户的平均报价总和”，这样的事情就可以了：

SELECT S.projectid, SUM(offers) FROM
  (
    SELECT projectid, clientid, AVG(price) as offers FROM sales WHERE active = 'yes'
    GROUP BY projectid, clientid
  ) AS S 
JOIN projects on S.projectid = projects.id
AND projects.active = "yes"
GROUP BY projectid

见http://sqlfiddle.com/#!2/19d0f/24

于 2013-07-31T15:03:19.667 回答