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假设我们有桌子 PEOPLE

id      |   name        |       extracted
-----------------------------------------
1       |   Roger       |
-----------------------------------------
2       |   Anthony     |
-----------------------------------------
3       |   Maria       |
-----------------------------------------

我们用

SELECT SUBSTRING(name, 1, 3) FROM people.name WHERE name like '%thon%'

它会找到“Anthony”并提取 3 个第一个字符 - 所以结果是：Ant

如何将此结果与相同的 id 放在一起，使表格看起来像

id      |   name        |       extracted
-----------------------------------------
1       |   Roger       |
-----------------------------------------
2       |   Anthony     |       Ant
-----------------------------------------
3       |   Maria       |
-----------------------------------------
4

1 回答 1

2

尝试

UPDATE people SET extracted = LEFT(`name`,3) WHERE `name` like '%thon%'
于 2013-07-31T13:22:30.163 回答