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我需要从 MySQL 表中提取数据并创建要在谷歌地图上显示的标记。

用于输出 xml 的 PHP 代码

<?php

function parseToXML($htmlStr) 
{ 
    $xmlStr=str_replace('<','&lt;',$htmlStr); 
    $xmlStr=str_replace('>','&gt;',$xmlStr); 
    $xmlStr=str_replace('"','&quot;',$xmlStr); 
    $xmlStr=str_replace("'",'&#39;',$xmlStr); 
    $xmlStr=str_replace("&",'&amp;',$xmlStr); 
    return $xmlStr; 
} 

$connection=mysql_connect (localhost, $username, $password);
if (!$connection) {
    die('Not connected : ' . mysql_error());
}

$db_selected = mysql_select_db('data1', $connection);
if (!$db_selected) {
    die ('Can\'t use db : ' . mysql_error());
}

$query = "SELECT * FROM health_block";
$result = mysql_query($query);
if (!$result) {
    die('Invalid query: ' . mysql_error());
}

header("Content-type: text/xml");
echo '<markers>';

while ($row = @mysql_fetch_assoc($result)){
    echo '<marker ';
    echo 'Hname="' . parseToXML($row['Hname']) . '" ';
    echo 'Lat="' . $row['Lat'] . '" ';
    echo 'Longt="' . $row['Longt'] . '" ';
    echo '/>';
}
echo '</markers>';
?>

下面是我用上面的代码得到的输出。（代码输出数据库表中的所有记录）：

<markers>
<marker Hname="CHC Anchuthengu" Lat="8.6734310" Longt="76.7581770"/>
<marker Hname="PHC Perumathura" Lat="8.6218640" Longt="76.7975220"/>
<marker Hname="PHC Keezhattingal" Lat="8.6982130" Longt="76.7915000"/>
<marker Hname="PHC Azhoor" Lat="8.6408080" Longt="76.8252470"/>

</markers>

用于在谷歌地图中显示标记的 PHP 主页

<!DOCTYPE html >
  <head>
    <meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
    <meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
    <title>PHP/MySQL & Google Maps Example</title>
    <script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?sensor=false"></script>
    <script type="text/javascript">
    //<![CDATA[

    var customIcons = {
      restaurant: {
        icon: 'http://labs.google.com/ridefinder/images/mm_20_blue.png',
        shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
      },
      bar: {
        icon: 'http://labs.google.com/ridefinder/images/mm_20_red.png',
        shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
      }
    };

    function load() {
      var map = new google.maps.Map(document.getElementById("map"), {
        center: new google.maps.LatLng(8.491118,76.949840),
        zoom: 12,
        mapTypeId: 'roadmap'
      });
      var infoWindow = new google.maps.InfoWindow;
      downloadUrl("phpsqlajax_genxml.php", function(data) {
        var xml = data.responseXML;
        var markers = xml.documentElement.getElementsByTagName("marker");
        for (var i = 0; i < markers.length; i++) {
          var hname = markers[i].getAttribute("Hname");
          var point = new google.maps.LatLng(parseFloat(markers[i].getAttribute("Lat")), parseFloat(markers[i].getAttribute("Longt")));
          var html = "<b>" + hname + "</b>";
          var icon = customIcons[type] || {};
          var marker = new google.maps.Marker({
            map: map,
            position: point,
            icon: icon.icon,
            shadow: icon.shadow
           });
           bindInfoWindow(marker, map, infoWindow, html);
        }
      });
    }
    function bindInfoWindow(marker, map, infoWindow, html) {
      google.maps.event.addListener(marker, 'click', function() {
        infoWindow.setContent(html);
        infoWindow.open(map, marker);
      });
    }
    function downloadUrl(url, callback) {
      var request = window.ActiveXObject ?
          new ActiveXObject('Microsoft.XMLHTTP') :
          new XMLHttpRequest;
      request.onreadystatechange = function() {
        if (request.readyState == 4) {
          request.onreadystatechange = doNothing;
          callback(request, request.status);
        }
      };
      request.open('GET', url, true);
      request.send(null);
    }

    function doNothing() {}
    //]]>

  </script>
  </head>
  <body onLoad="load()">
  <div id="map" style="width: 1400px; height: 800px"></div>
  </body>
</html>

在浏览器中执行此代码时，它会正确显示谷歌地图。但是我的标记没有显示。如果您能提供帮助，那就太好了。

谢谢
珍妮

4

1 回答 1

0

我在 IE 中收到此错误：

Message: 'type' is undefined
Line: 38
Char: 7
Code: 0

这在 Chrome 中：

Uncaught ReferenceError: type is not defined v3_SO_PHPMySQL.html:38

如果我修复它（通过定义它var type = "bar";），我会看到标记。

    function load() {
      var map = new google.maps.Map(document.getElementById("map"), {
        center: new google.maps.LatLng(8.491118,76.949840),
        zoom: 11,
        mapTypeId: 'roadmap'
      });
      var infoWindow = new google.maps.InfoWindow;
      downloadUrl("SO_phpsqlajax_genxml_20130731.xml", function(data) {
        var xml = data.responseXML;
        var markers = xml.getElementsByTagName("marker");
        for (var i = 0; i < markers.length; i++) {
          var hname = markers[i].getAttribute("Hname");
          var point = new google.maps.LatLng(parseFloat(markers[i].getAttribute("Lat")), parseFloat(markers[i].getAttribute("Longt")));
      var html = "<b>" + hname + "</b>";
      var type = "bar";
      var icon = customIcons[type] || {};
      var marker = new google.maps.Marker({
        map: map,
        position: point,
        icon: icon.icon,
        shadow: icon.shadow
          });
          bindInfoWindow(marker, map, infoWindow, html);
        }
      });
    }

工作示例

于 2013-07-31T12:05:45.757 回答