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任何人都可以帮助我或建议一个很好的示例/教程，说明我将如何使用 JSON 和 httpost 将值发布到网站。我想要做的是将以下值提交到网站：

("DateObserved", _date);
("ProvinceId", "59");
("InformationTypeId", "3");
("ReportTypeId","3");
("IsCompetitor",_competitor);
("SubBrands","91");
("ConsumerSegments","3");

对于我作为 android 的新手来说，应用我在 SO 的不同帖子中读到的内容有点困难，所以我只想要求一个很好的例子或教程来帮助我理解它。无论如何，我已经为此尝试了一些方法，但我得到了 ClientProtocolException。我真的不知道我错过了什么。请帮帮我...

HttpParams httpParameters = new BasicHttpParams();

        HttpConnectionParams.setConnectionTimeout(httpParameters, 15000);
        HttpConnectionParams.setSoTimeout(httpParameters, 15000);           

        HttpClient httpclient = new DefaultHttpClient(httpParameters);
        HttpPost httpPost = new HttpPost("http://svr4.sampleserver.com:0727/api/reports");



        JSONObject report = new JSONObject();
        report.put("IsCompetitor", _competitor);
        report.put("DateObserved", _date);
        report.put("ProvinceId", "59");
        report.put("InformationTypeId", "3");
        report.put("ReportTypeId","3");
        report.put("IsCompetitor",_competitor);
        report.put("SubBrands","91");
        report.put("ConsumerSegments","3");



         StringEntity entity1 = new StringEntity(report.toString(), HTTP.UTF_8);
         entity1.setContentType("application/json");
         httpPost.setEntity(entity1);

         httpPost.setHeader("Content-type", "application/json");
            HttpResponse response = httpclient.execute(httpPost);
            HttpEntity entity = response.getEntity();

         Log.e("ReportCode",_competitor); 
           // in.close();

    }catch (Exception e){
    Log.e("ClientServerDemo", "Error:", e);
    exception = e;
    //Toast.makeText(getApplicationContext(), e.getMessage().toString(), 5).show();
}

日志猫：

 08-01 18:56:29.668: E/ClientServerDemo(2283): org.apache.http.client.ClientProtocolException
 08-01 18:56:29.668: E/ClientServerDemo(2283):  at   org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:557)
 08-01 18:56:29.668: E/ClientServerDemo(2283):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487)
 08-01 18:56:29.668: E/ClientServerDemo(2283):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at com.undfgfgdfb.ireport.DoPost.doInBackground(DoPost.java:102)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at com.undfgfgdfb.ireport.DoPost.doInBackground(DoPost.java:1)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at android.os.AsyncTask$2.call(AsyncTask.java:252)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
 08-01 18:56:29.668: E/ClientServerDemo(2283):  at java.util.concurrent.FutureTask.run(FutureTask.java:137)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1081)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:574)
08-01 18:56:29.668: E/ClientServerDemo(2283):   at java.lang.Thread.run(Thread.java:1020)
08-01 18:56:29.668: E/ClientServerDemo(2283): Caused by: org.apache.http.auth.MalformedChallengeException: Authentication challenge is empty
08-01 18:56:29.668: E/ClientServerDemo(2283):   at org.apache.http.impl.auth.RFC2617Scheme.parseChallenge(RFC2617Scheme.java:72)

08-01 18:56:29.668: E/ClientServerDemo(2283): at org.apache.http.impl.auth.AuthSchemeBase.processChallenge(AuthSchemeBase.java:111) 08-01 18:56:29.668: E/ClientServerDemo( 2283): 在 org.apache.http.impl.auth.BasicScheme.processChallenge(BasicScheme.java:95) 08-01 18:56:29.668: E/ClientServerDemo(2283): 在 org.apache.http.impl.client .DefaultRequestDirector.processChallenges(DefaultRequestDirector.java:1071) 08-01 18:56:29.668: E/ClientServerDemo(2283): at org.apache.http.impl.client.DefaultRequestDirector.handleResponse(DefaultRequestDirector.java:968) 08- 01 18:56:29.668: E/ClientServerDemo(2283): 在 org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:478) 08-01 18:56:29.668: E/ClientServerDemo(2283) : 在 org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 08-01 18:56:29.668: E/ClientServerDemo(2283): ... 10 更多

4

1 回答 1

0

我做了类似以下对我有用的事情，

String  responseBody = null;
        HttpPost post = new HttpPost("http://XXXXXXXXX");
        String udid = "XXXXX"; 
        String device_token = "********"; 
        JSONObject jObj = new JSONObject(); 
        try {
        jObj.put("udid", udid);
            jObj.put("device_token", device_token);

        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }         
        StringEntity se = null;
        try {
            se = new StringEntity(jObj.toString());
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } 
        post.setEntity(se); 
        post.setHeader(new BasicHeader(HTTP.CONTENT_TYPE, "application/json")); 
        post.setHeader("Content-type", "application/json"); 
        ResponseHandler<String> responseHandler = new BasicResponseHandler(); 
        HttpClient client = new DefaultHttpClient();
        try {
              responseBody = client.execute(post, responseHandler);
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return responseBody;
于 2013-07-31T10:59:51.393 回答