该文件包含在我的索引文件中，我希望页面上和帖子 1 2 3 4... 等下的帖子不超过 5 个（链接到下一页），并且看起来像这样 index.php?page= 2 对不起我的语法不好。
<?php
if(isset($_GET['post_edit'])) {
$p_id = $_GET['post_edit'];
$p_query = mysql_query("SELECT title, post FROM posts WHERE id='$p_id'");
$p_array = mysql_fetch_array($p_query);
$title = $p_array['title'];
$post = $p_array['post'];
}
?>
<?php
if(isset($_POST['edit'])){
$title_edit = $_POST['titleedit'];
$post_edit = $_POST['postedit'];
if(empty($title) or empty($post)){
echo "<p>Fields empty!</p>";
} else {
mysql_query("UPDATE posts SET title='$title_edit', post='$post_edit' WHERE id='$p_id'");
echo "Edit succesful!</br>";
header('location: index.php');
}
}
?>
<?php
if(isset($_GET['post_edit']) && !empty($_GET['post_edit'])){
include 'edit_post.php';
} else {
?>
<?php
$query = mysql_query("SELECT * FROM posts ORDER BY date DESC");
while($row = mysql_fetch_array($query)){
echo "<div class='poststitle'>";
echo "<div style='font-weight: bold;'>";
echo $row['title'];
echo "</div>";
echo "</div>";
echo "<div class='posts'>";
echo $row['post'];
echo "</br>";
echo "<hr>";
$user_name = mysql_query("SELECT username FROM users WHERE id = '".$row['user']."' ");
$user_name_array = mysql_fetch_array($user_name);
$post_id = $row['id'];
echo "Posted by: <b>";
echo $user_name_array['username'];
echo "</b> | ";
echo "Views: <b>";
echo $row['views'];
echo "</b> | ";
echo "Posted on: ";
echo "<b>";
echo $row['date'];
echo "</b><hr>";
echo '</div>';
if (loggedin()){
if($user_level == 1){
echo "<div class='postoptions'>";
echo "<a href='index.php?post_edit=$post_id'><img src='img/optionicons/edit.png' width='15' height='15' alt='edit' /></a>";
echo "<a href='del_post.php?del=$post_id'><img src='img/optionicons/cancel.png' width='15' height='15' alt='Delete' /></a>";
echo "</div>";
} else {
echo "";
}
}
}
}
?>