1

我正在尝试查找本周的记录数。我目前的查询是：

SELECT Week(Str_to_date(products_options_values, '%m-%d-%Y'), 1) AS order_week,
       Year(Str_to_date(products_options_values, '%m-%d-%Y')) AS order_year,
       order_active,
       Count(op.sub_order_id) AS deliveries
FROM   orders_products_attributes opa
       LEFT JOIN orders_products op
              ON ( opa.orders_products_id = op.orders_products_id )
GROUP  BY order_week,
          order_year
HAVING order_week = '31'
       AND order_year >= '2013'
       AND order_active = 0
ORDER  BY order_week

它在实际有 4 条记录的情况下获取deliveriesAS 2，如果我在删除COUNTand后运行相同的查询GROUP BY，它会正确显示所有 4 行。同样的问题也发生在其他周，例如第 34 周有 3 条记录，但上面的查询将其获取为 4。此外，另一个奇怪的事情是，在GROUP BY子句中，如果我删除其中一个order_week或order_year查询返回一个空结果集。

知道我做错了什么吗？

4

1 回答 1

0

尝试将所有 HAVING 条件移动到 WHERE。此外Count(id)- 计算 ID 的唯一值不是全部。如果您需要所有记录计数，请使用COUNT(*)

SELECT Week(Str_to_date(products_options_values, '%m-%d-%Y'), 1) AS order_week,
       Year(Str_to_date(products_options_values, '%m-%d-%Y')) AS order_year,
       order_active,
       Count(op.sub_order_id) AS deliveries
FROM   orders_products_attributes opa
       LEFT JOIN orders_products op
              ON ( opa.orders_products_id = op.orders_products_id )
WHERE order_week = '31'
       AND order_year >= '2013'
       AND order_active = 0

GROUP  BY order_week,
          order_year
ORDER  BY order_week
于 2013-07-31T06:43:06.867 回答