3

我有一个 Powershell 脚本，它读取一个文本文件，其中包含共享及其属性的单行描述。

然后，对于每个共享，它会将一个具有属性的对象添加到一个数组中。

我最终得到了一系列股票，其中许多具有共同的属性，但也有一些只出现在少数股票上。

当我将完成的数组通过管道传输到Export-CSV时，生成的 CSV 仅包含与数组中第一个对象的属性匹配的列。

感激地收到任何想法/帮助。

这是代码：

$shares_only = gc \\server\share\SHARES.txt | where {$_ -match '^*TYPE = DISK'}

$share_index = @()

$shares_only |foreach {

    $sharename = ($_.Split(" ")[1])
    $_ -match '\([\w\s.,"=<>()\/\*\+\-]*\);'|out-null

    $shareparams = $matches[0]

    $paramlist = ($shareparams.Substring(1,($shareparams.Length -3))).Split(",")

    $obj = $null
    $obj = New-Object System.Object

    $obj | Add-Member -type NoteProperty -Name NAME -Value $sharename

    $paramlist | foreach {
        $obj `
        | Add-Member -type NoteProperty -Name ($_.Split("=")[0]) -Value ($_.Split("=")[1])
    }
    $share_index += $obj
}

$share_index | Select * | Export-CSV -notype \\server\share\Shares.csv

这里以数组中的前两个对象为例（$share_index[0..2]用于输出到控制台）：

NAME          : _ACCTEST_
TYPE          :  DISK 
PREFIX        :  (<USERCODE>) 
AREABYTES     :  184320 
ACCESS        :  ALL 
FAMILY        :  ACCTESTPACK 
DOWNSIZEAREA  :  TRUE 

NAME              : _HOME_
TYPE              :  DISK 
PREFIX            :  (<USERCODE>) 
COMMENT           :  Private user files 
AREABYTES         :  184320 
ACCESS            :  ALL -EXTRACT 
FAMILY            :  <FAMILY> 
DOWNSIZEAREA      :  TRUE 
ALLOWGUESTACCESS  :  TRUE

这是 CSV 的前 3 行：

"NAME","TYPE ","PREFIX ","AREABYTES ","ACCESS ","FAMILY ","DOWNSIZEAREA "
"_ACCTEST_"," DISK "," (<USERCODE>) "," 184320 "," ALL "," ACCTESTPACK "," TRUE "
"_HOME_"," DISK "," (<USERCODE>) "," 184320 "," ALL -EXTRACT "," <FAMILY> "," TRUE "

您可以看到COMMENT和ALLOWGUESTACCESS属性丢失，即使它们位于_HOME_共享的数组中。

编辑：接受@JPBlancs 答案的略微修改版本，所以我的代码的最后两行现在是：

$fixed_index = $share_index | Sort-Object -Property @{expression={(($_.psobject.Properties)|Measure-Object).count}} -Descending | ConvertTo-CSV -notype
$fixed_index | ConvertFrom-CSV | Sort -Property Name | Export-CSV -notype \\server\share\Shares.csv

因此，按照建议完成，然后在新对象中转换为 CSV。然后，将该对象从 CSV 转换回来，保留新属性，再次按名称排序以获得我需要的字母列表，然后再次导出到 CSV。

给我，例如：

"NAME","TYPE","PREFIX","PUBLIC","COMMENT","AREABYTES","ACCESS","FAMILY","DOWNSIZEAREA","ALLOWGUESTACCESS"
"_ACCTEST_"," DISK "," (<USERCODE>) ","",""," 184320 "," ALL "," ACCTESTPACK "," TRUE ",
"_HOME_"," DISK "," (<USERCODE>) ",""," Private user files "," 184320 "," ALL -EXTRACT "," <FAMILY> "," TRUE "," TRUE "
4

4 回答 4

4

Export-Csv并且ConvertTo-Csv似乎只采用发送给它们的对象之间的属性联合。我认为您必须解析文本文件并编译所有属性的列表，并在创建对象时将任何缺少的属性值设置为 null。

于 2013-07-31T00:42:09.657 回答
3

我做了这样的事情

$a = "" | select "P1","P2"
$b = "" | select "P1","P2","P3"
$c = "" | select "P1","P2","P3","P4"
$array = $a,$b,$c
$array | Export-Csv c:\temp\t.csv

正如你所说：

#TYPE Selected.System.String
"P1","P2"
,
,
,

所以想法是按属性计数对对象进行排序：

$array | Sort-Object -Property @{expression={$_.psobject.properties.count}} -Descending| Export-Csv c:\temp\t.csv

它给 ：

#TYPE Selected.System.String
"P1","P2","P3","P4"
,,,
,,,
,,,

对于问题（创建的对象将成员添加到 System.Object），您可以使用：

Sort-Object -Property @{expression={(($_.psobject.Properties)|Measure-Object).count}} -Descending
于 2013-07-31T07:12:33.070 回答
0

我使用以下代码：

$a = "" | select "P1","P2"
$b = "" | select "P1","P2","P3"
$c = "" | select "P1","P2","P3","P4"
$props=@{n='P1';e={$_.p1}},@{n='P2';e={$_.p2}},@{n='P3';e={$_.p3}},@{n='P4';e={$_.p4}}
$array = $a,$b,$c
$array | select $props|Export-Csv c:\temp\t.csv
于 2014-02-25T09:19:18.930 回答
0

JPBlanc 的解决方案并不总是有效，因为最长的对象数组不必是较小数组的超集（例如，它不适用于下面显示的示例，其中所有对象都具有不同的属性但数量没有差异特性）。

我通常可以按如下方式解决此问题：

$a = "" | select "P1","P2"
$b = "" | select "P2","P3"
$c = "" | select "P3","P4"
$array = $a,$b,$c
$array | Select ($array | ForEach {$_ | Get-Member -MemberType NoteProperty | Select -ExpandProperty Name} | Select -Unique) | Export-Csv ".\Union.csv"

不幸的是，这不适用于包含不同类型对象的 WMI 查询，但它适用于以下 cmdlet：

Function Union-Object {
    $Output = @()
    $Input | ForEach {
        If ($Output.Count) {$_ | Get-Member | Where {!($Output[0] | Get-Member $_.Name)} | ForEach {$Output[0] | Add-Member NoteProperty $_.Name $Null}}
        $Output += $_
    }
    $Output
}; Set-Alias Union Union-Object

用法：

$array | Union | Export-Csv ".\Union.csv"
于 2016-11-08T13:13:33.677 回答