2

我是 play-framework 的新手（与 JSF/seam 相比，我希望它可以简化 Web 开发）并且遇到了数据源问题（不幸的是，文档对这个问题并没有真正的帮助）：

我将需要多个数据源，因此数据源的名称与“默认”不同。

这是application.conf：

db.monitoring.driver=org.postgresql.Driver
db.monitoring.url="jdbc:postgresql://localhost/skiline_monitoring"
db.monitoring.user=skiline
db.monitoring.password=skiline

ebean.monitoring="models.monitoring.*"

监控数据源的模型类位于包 models.monitoring 中。

模型类：

@Entity
public class SystemProperty extends Model {
    @Column(length=100)
    public String key;
    @Column(length=1000)
    public String value;

    public static Finder<SystemPropertyKey, SystemProperty> find() {
        return new Finder<SystemPropertyKey, SystemProperty>(SystemPropertyKey.class,      
            SystemProperty.class);
    }        
}

第一次调用 SystemProperty.find().all() 会产生以下异常：

play.api.Application$$anon$1: Execution exception[[RuntimeException: DataSource user is null?]]
    at play.api.Application$class.handleError(Application.scala:289) ~[play_2.10.jar:2.1.2]
    at play.api.DefaultApplication.handleError(Application.scala:383) [play_2.10.jar:2.1.2]
    at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$play$core$server$netty$PlayDefaultUpstreamHandler$$handle$1$1.apply(PlayDefaultUpstreamHandler.scala:143) [play_2.10.jar:2.1.2]
    at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$play$core$server$netty$PlayDefaultUpstreamHandler$$handle$1$1.apply(PlayDefaultUpstreamHandler.scala:139) [play_2.10.jar:2.1.2]
    at play.api.libs.concurrent.PlayPromise$$anonfun$extend1$1.apply(Promise.scala:113) [play_2.10.jar:2.1.2]
    at play.api.libs.concurrent.PlayPromise$$anonfun$extend1$1.apply(Promise.scala:113) [play_2.10.jar:2.1.2]
java.lang.RuntimeException: DataSource user is null?
    at com.avaje.ebeaninternal.server.lib.sql.DataSourcePool.<init>(DataSourcePool.java:184) ~[avaje-ebeanorm-server.jar:na]
    at com.avaje.ebeaninternal.server.lib.sql.DataSourceManager.getDataSource(DataSourceManager.java:200) ~[avaje-ebeanorm-server.jar:na]
    at com.avaje.ebeaninternal.server.lib.sql.DataSourceGlobalManager.getDataSource(DataSourceGlobalManager.java:46) ~[avaje-ebeanorm-server.jar:na]
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.getDataSourceFromConfig(DefaultServerFactory.java:432) ~[avaje-ebeanorm-server.jar:na]
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.setDataSource(DefaultServerFactory.java:393) ~[avaje-ebeanorm-server.jar:na]
    at com.avaje.ebeaninternal.server.core.DefaultServerFactory.createServer(DefaultServerFactory.java:169) ~[avaje-ebeanorm-server.jar:na]

将文件 ebean.properties 添加到 conf/ 目录没有帮助。conf/ebean.properties 看起来像这样：

datasource.default=monitoring

datasource.monitoring.username=skiline
datasource.monitoring.password=skiline
datasource.monitoring.databaseUrl=jdbc:postgresql://localhost/skiline_monitoring
datasource.monitoring.databaseDriver=org.postgresql.Driver
datasource.monitoring.minConnections=1
datasource.monitoring.maxConnections=25
datasource.monitoring.heartbeatsql=select 1
datasource.monitoring.isolationlevel=read_committed

有什么想法，我在这里缺少什么（我使用的是最新的稳定版本 2.1.2）？

4

1 回答 1

4

经过一番调试，我发现了问题：

如果数据源的名称与“默认”不同，则必须在创建查找器时指定服务器名称。

所以

public static Finder<SystemPropertyKey, SystemProperty> find() {
    return new Finder<SystemPropertyKey, SystemProperty>(SystemPropertyKey.class,      
        SystemProperty.class);
}

必须改为

public static Finder<SystemPropertyKey, SystemProperty> find() {
    return new Finder<SystemPropertyKey, SystemProperty>("monitoring", 
        SystemPropertyKey.class, SystemProperty.class);
}
于 2013-07-31T05:46:53.157 回答