5

我正在尝试对此表进行查询：

Id       startdate     enddate       amount
1        2013-01-01   2013-01-31      0.00
2        2013-02-01   2013-02-28      0.00
3        2013-03-01   2013-03-31      245
4        2013-04-01   2013-04-30      529
5        2013-05-01   2013-05-31      0.00
6        2013-06-01   2013-06-30      383
7        2013-07-01   2013-07-31      0.00
8        2013-08-01   2013-08-31      0.00

我想得到输出：

2013-01-01          2013-02-28          0
2013-03-01          2013-06-30          1157
2013-07-01          2013-08-31           0

我想得到那个结果，这样我就可以知道钱什么时候开始进来，什么时候停止。我也对资金开始进入前的月数感兴趣（这解释了第一行），以及资金停止的月数（这解释了为什么我也对 2013 年 7 月至 2013 年 8 月的第三行感兴趣）。

我知道我可以在日期上使用 min 和 max 并在金额上使用总和，但我不知道如何以这种方式划分记录。
谢谢！

4

6 回答 6

4 
with CT as
(
    select t1.*,
           ( select max(endDate) 
             from t 
             where startDate<t1.StartDate and SIGN(amount)<>SIGN(t1.Amount)
           ) as GroupDate
    from t  as t1
) 
select min(StartDate) as StartDate,
       max(EndDate) as EndDate,
       sum(Amount) as Amount
from CT
group by GroupDate
order by StartDate

SQLFiddle 演示

于 2013-07-30T13:13:15.853 回答
2

这是一个想法（和一个小提琴）：

;WITH MoneyComingIn AS
(
    SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, 
        SUM(amount) AS amount
    FROM myTable
    WHERE amount > 0
)
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, 
    SUM(amount) AS amount
FROM myTable
WHERE enddate < (SELECT startdate FROM MoneyComingIn)
UNION ALL
SELECT startdate, enddate, amount
FROM MoneyComingIn
UNION ALL
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, 
    SUM(amount) AS amount
FROM myTable
WHERE startdate > (SELECT enddate FROM MoneyComingIn)

第二个，不使用UNION（小提琴）：

SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM
(
    SELECT startdate, enddate, amount,
    CASE 
        WHEN EXISTS(SELECT 1 
                    FROM myTable b 
                    WHERE b.id>=a.id AND b.amount > 0) THEN
            CASE WHEN EXISTS(SELECT 1 
                             FROM myTable b 
                             WHERE b.id<=a.id AND b.amount > 0) 
                 THEN 2 
                 ELSE 1 
            END
        ELSE 3
    END AS partition_no
    FROM myTable a
) x
GROUP BY partition_no

虽然我认为它假设Id是按顺序写的。你可以用ROW_NUMBER() OVER(ORDER BY startdate).

于 2013-07-30T13:08:58.553 回答
1

应该这样做：

select min(startdate), max(enddate), sum(amount) from paiements
   where enddate   < (select min(startdate) from paiements where amount >0)
union
select min(startdate), max(enddate), sum(amount) from paiements
   where startdate >= (select min(startdate) from paiements where amount >0)
     and enddate   <= (select max(enddate) from paiements where amount >0)
union
select min(startdate), max(enddate), sum(amount) from paiements
   where startdate > (select max(enddate) from paiements where amount >0)

但是对于这种报告，使用多个查询可能更明确。

于 2013-07-30T13:10:07.640 回答
1

这可以满足您的要求：

-- determine the three periods
DECLARE @StartMoneyIn INT
DECLARE @EndMoneyIn INT

SELECT @StartMoneyIn = MIN(Id)
FROM [Amounts]
WHERE amount > 0

SELECT @EndMoneyIn = MAX(Id)
FROM [Amounts]
WHERE amount > 0

-- retrieve the amounts
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, SUM(amount) AS amount
FROM [Amounts]
WHERE Id < @StartMoneyIn
UNION
SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM [Amounts]
WHERE Id >= @StartMoneyIn AND Id <= @EndMoneyIn
UNION
SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM [Amounts]
WHERE Id > @EndMoneyIn
于 2013-07-30T13:11:34.267 回答
0

如果您只想查看资金何时开始流入以及何时停止，这可能对您有用：

select 
    min(startdate),
    max(enddate),
    sum(amount)
where
    amount > 0

这不包括没有钱进来的时期。

于 2013-07-30T13:05:07.570 回答
0

如果您不关心该期间的总数，而只想要从 0 到某事的记录，反之亦然，您可以像这样疯狂地做一些事情：

select *
from MoneyTable mt
where exists ( select *
               from MoneyTable mtTemp
               where mtTemp.enddate = dateadd(day, -1, mt.startDate)
               and mtTemp.amount <> mt.amount
               and mtTemp.amount * mt.amount = 0)

或者，如果您必须包含第一条记录：

select *
from MoneyTable mt
where exists ( select *
               from MoneyTable mtTemp
               where mtTemp.enddate = dateadd(day, -1, mt.startDate)
               and mtTemp.amount <> mt.amount
               and mtTemp.amount * mt.amount = 0 )
or not exists ( select *
                from MoneyTable mtTemp
                where mtTemp.enddate = dateadd(day, -1, mt.startDate))

Sql 小提琴

于 2013-07-30T13:33:58.173 回答