-1

我正在制作一个 android 应用程序，它从带有编码 JSON 的网页中检索数据。当我在网络浏览器中访问该页面时，它要求我进行服务器身份验证，我在其中输入我的用户名和密码。当我做一个 httpPost 时，我是怎么做到的；它将发送一个用户名和密码，以便我可以访问该页面。

它的这种身份验证http://www.wpwhitesecurity.com/wp-content/uploads/2012/08/web-server-authentication-dialogue-box.png

我该怎么做呢？这是我的代码：

            DefaultHttpClient httpClient = new DefaultHttpClient();


        HttpPost httpPost = new HttpPost(url);

        HttpResponse httpResponse = null;
        try {
            httpResponse = httpClient.execute(httpPost);
        } catch (ClientProtocolException e2) {
            // TODO Auto-generated catch block
            e2.printStackTrace();
        } catch (IOException e2) {
            // TODO Auto-generated catch block
            e2.printStackTrace();
        }
        HttpEntity httpEntity = httpResponse.getEntity();
        try {
            is = httpEntity.getContent();
        } catch (IllegalStateException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        } catch (IOException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }
4

3 回答 3

0

您可以像这样发送您的用户名和密码：

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair(your_username_key_string, your_username));
nameValuePairs.add(new BasicNameValuePair(your_password_key_string, your_password));            

HttpPost oHttpPost = new HttpPost(your_server_url);
oHttpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
于 2013-07-30T10:53:14.153 回答
0

好的......所以你可以通过它：

DefaultHttpClient httpClient = new DefaultHttpClient();

String url = "yoururl"+"username="+YourUsername+"password="+Your Paasword;

    HttpPost httpPost = new HttpPost(url);

    HttpResponse httpResponse = null;
    try {
        httpResponse = httpClient.execute(httpPost);
    } catch (ClientProtocolException e2) {
        // TODO Auto-generated catch block
        e2.printStackTrace();
    } catch (IOException e2) {
        // TODO Auto-generated catch block
        e2.printStackTrace();
    }
    HttpEntity httpEntity = httpResponse.getEntity();
    try {
        is = httpEntity.getContent();
    } catch (IllegalStateException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
于 2013-07-30T10:53:41.937 回答
0

将您的参数添加到帖子中：

final List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("username", username));  
nameValuePairs.add(new BasicNameValuePair("password", password));  
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs, HTTP.UTF_8));

这是假设您的登录表单如下所示：

input type="text" name="username"
input type="password" name="password"
于 2013-07-30T10:56:16.673 回答