0

在我们的项目中，我必须使用带有以下数据的算法 AES 128 CBC：

KEY = "abcdef0123456789abcdef0123456789"

IV =“00000000000000000000000000000000”

要加密的文本是

2~1~000024~0910~20130723092446~T~00002000~USD~F~375019001012120~0~0~00000000000~

预期的结果是

0D 58 35 AF EB EE 04 C6 DC 24 21 53 8D B7 C3 8A 12 83 97 0E B3 1F 21 A4 7D 2E 3C C6 23 D2 9E F0 46 12 79 C7 AC F9 3B 03 1B E2 B6 9C E4 5C 93 39 5 57 F2 9E F6 09 F0 19 EE C9 75 98 3A 03 B5 37 62 2D 7E 0F 19 6B E1 48 F1 C7 CB B8 8E 60 2A

结果文本的长度为 160 个字符。

我尝试使用许多算法，但我的所有结果都不同。

您会用自己的方法加密文本并使用预期结果进行验证吗？

你会粘贴你的结果吗？

这是我的测试：

$cipher = mcrypt_module_open(MCRYPT_RIJNDAEL_128, '', MCRYPT_MODE_CBC, '');

$data_to_encrypt = "2~1~000024~0910~20130723092446~T~00002000~USD~F~375019001012120~0~0~00000000000~";
$key128 = "abcdef0123456789abcdef0123456789";
$iv = "0000000000000000"."0000000000000000";

echo "data_to_encrypt: ".$data_to_encrypt."<br/>";

if (($res = mcrypt_generic_init($cipher, $key128, $iv)) != -1)
{
    // PHP pads with NULL bytes if $cleartext is not a multiple of the block size.
    $cipherText = mcrypt_generic($cipher,$data_to_encrypt);
    mcrypt_generic_deinit($cipher);
    $data_encrypted = strtoupper(bin2hex($cipherText));
    echo "result encrypt: ".$data_encrypted."<br/>";
    echo "len: ".strlen($data_encrypted)."<br/>";
}

这是我的回答：

data_to_encrypt: 2~1~000024~0910~20130723092446~T~00002000~USD~F~375019001012120~0~0~00000000000~ result encrypt: C9A4E600BAC6FC4F2077FF62DDB5F9BEAB1C9C567A98E6B81373711A4BC0FFE1748F5E26886896AB87CD375567C5466E6A9F4C079AD19B592E080896BCFDB52324F342A9F94AE71FADB1F6820EB57F7B len: 160

提前感谢您的帮助和时间。

4

2 回答 2

2

这个 C 程序给出了正确的结果：

#include <stdio.h>
#include <openssl/aes.h>

int main()
{
unsigned char key[16] =     {0xab,0xcd,0xef,0x01,0x23,0x45,0x67,0x89,0xab,0xcd,0xef,0x01,0x23,0x45,0x67,0x89};
unsigned char iv[16] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
unsigned char plaintext[] = {
    '2','~','1','~','0','0','0','0','2','4','~','0','9','1','0','~',
    '2','0','1','3','0','7','2','3','0','9','2','4','4','6','~','T',
    '~','0','0','0','0','2','0','0','0','~','U','S','D','~','F','~',
    '3','7','5','0','1','9','0','0','1','0','1','2','1','2','0','~',
    '0','~','0','~','0','0','0','0','0','0','0','0','0','0','0','~',
};
unsigned char ciphertext[sizeof(plaintext)];
AES_KEY aes;
size_t i;

AES_set_encrypt_key(key,128,&aes);
AES_cbc_encrypt(plaintext,ciphertext,sizeof(plaintext),&aes,iv,AES_ENCRYPT);

for(i=0; i<sizeof(ciphertext); i++) {
    printf("%02x ", ciphertext[i]);
}
printf("\n");

return 0;
}

gcc -o test test.c -lcrypto

./test

0d 58 35 af eb ee 04 c6 dc 24 21 53 8d b7 c3 8a 12 83 97 0e b3 1f 21 a4 7d 2e 3c c6 23 d2 9e f0 46 12 79 c7 ac f9 3b 03 1b e2 b6 9c e4 5c 93 39 55 49 57 f2 9e f6 09 f0 19 ee c9 75 98 3a 03 b5 37 62 2d 7e 0f 19 6b e1 48 f1 c7 cb b8 8e 60 2a

您的问题是您需要在使用它们之前将您的密钥和 IV 字符串反十六进制转换为字节。

于 2013-07-30T16:40:07.877 回答
1

首先，我要感谢所有向我发送建议的人，

现在，我与您分享我的问题的解决方案，

我希望它也对任何人有帮助，

<?php

function hex2bin($hex_string) {
    return pack('H*', $hex_string);
}

$data_to_encrypt = '2~1~000024~0910~20130723092446~T~00002000~USD~F~375019001012120~0~0~00000000000~';
$key = 'abcdef0123456789abcdef0123456789';
$iv = '0000000000000000';

$key = hex2bin($key);
$iv = hex2bin($iv);

$data_encrypted = bin2hex(mcrypt_encrypt(MCRYPT_RIJNDAEL_128, $key, $data_to_encrypt, MCRYPT_MODE_CBC, $iv));
echo "Data encrypted: ".strtoupper($data_encrypted)."<br/>";
echo "Length: ".strlen($data_encrypted)."<br/>";

?>

Data encrypted: 0D5835AFEBEE04C6DC2421538DB7C38A1283970EB31F21A47D2E3CC623D29EF0461279C7ACF93B031BE2B69CE45C9339554957F29EF609F019EEC975983A03B537622D7E0F196BE148F1C7CBB88E602A

长度：160

上帝祝福你

于 2013-07-31T10:05:27.007 回答