0

我已经通过正常渠道尝试解决此问题,但我似乎无法确定如何将数据正确地从我的 Android 应用程序发送到托管在我的 C# winforms 应用程序中的 WCF 库。

我已经使用 Visual Studio 提供的 WCFClientTest 应用程序检查了该服务是否正确托管,并且一切都在这方面工作。当我调用此行时: androidHttpTransport.call(SOAP_ACTION, envelope); 它似乎挂在 Android 应用程序中

我正在使用 ksoap2 尝试调用 WCF 服务,并使用此链接作为教程。

安卓代码

private static final String METHOD_NAME = "Alive";
    private static final String NAMESPACE = "http://tempuri.org/";
    private static final String SOAP_ACTION 
                               = "http://tempuri.org/IDeviceHealth/Alive";

    //10.0.2.2 is the ip address for the device simulator.
    private static final String URL = "http://192.168.1.8:8733/DeviceHealth/HealthService/mex"; 

    //SOAP must be  the same version as the webservice.
    private static final int SOAP_VERSION = SoapEnvelope.VER12;

public void OnClickGoBtn(View v)
    {
        try 
        {
         SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        SoapSerializationEnvelope envelope
                                     = new SoapSerializationEnvelope(SOAP_VERSION);
        envelope.dotNet = true;
            envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

        androidHttpTransport.call(SOAP_ACTION, envelope);
        Object result = envelope.getResponse();

        String resultData = result.toString();
        Log.d("WCF Response", resultData);          
        } 
        catch (IOException e) 
        {
          Log.d("WCF IO Error", e.toString());
        }
        catch (XmlPullParserException e) 
        {
            Log.d("XML Pull Error",e.toString());
        }
        catch(Exception e)
        {
            Log.d("General Exception", e.toString());
        }
    }

C# 服务器:

 <behaviors>
      <serviceBehaviors>
        <behavior name="MetadataBehavior">
          <serviceMetadata httpGetEnabled="true" />
        </behavior>
      </serviceBehaviors>
    </behaviors>

    <services>
      <service name="DeviceHealthService.DeviceHealth" behaviorConfiguration="MetadataBehavior">

        <endpoint address=""
                  binding="netTcpBinding"
                  contract="DeviceHealthService.IDeviceHealth"/>

        <endpoint address="mex"
                  binding="mexHttpBinding"
                  contract="IMetadataExchange"/>

        <host>
          <baseAddresses>
            <add baseAddress="net.tcp://localhost:10001"/>
            <add baseAddress="http://localhost:10002"/>
          </baseAddresses>
        </host>

      </service>
    </services>

public string Alive()
        {
            return "I am running";
        }
4

1 回答 1

0

您应该在 AsyncTask 中执行此操作,而不是在主线程中!从您的帖子来看,您似乎是从主线程中执行此操作的。

关于您的代码的其他所有内容看起来都很正常。我通常使用超时,但我看你没有。

要注意的另一件事是,您将 URL 指向“localhost”,但您的 android 设备不知道 localhost 是什么。您应该指向 10.0.2.2。

如果有帮助,这是我在我的一个使用基于 SOAP 的 WCF 服务的 Android 应用程序中使用的实用程序方法。请注意,我总是在 AsyncTask 中调用它,而不是在主线程中。

public static String invokeSoapWebservice(String method, Bundle properties, int timeout) throws IOException, XmlPullParserException {

    String action = SOAP_ACTION + method;       

    System.out.println("Calling web method " + method);

    SoapObject request = new SoapObject(NAMESPACE, method);

    //Note - ORDER MATTERS HERE
    //If the web method takes employeeId, workSiteId, jobId in that order, 
    //they have to be added to the request in that order (what bullshit!)

    if(properties.containsKey("loginId")) {
        request.addProperty("loginId", properties.getInt("loginId"));
        System.out.println("loginId = " + properties.getInt("loginId"));
    }

    if(properties.containsKey("employeeId")) {
        request.addProperty("employeeId", properties.getInt("employeeId"));
        System.out.println("employeeId = " + properties.getInt("employeeId"));
    }

    if(properties.containsKey("workSiteId")) {
        request.addProperty("workSiteId", properties.getInt("workSiteId"));
        System.out.println("workSiteId = " + properties.getInt("workSiteId"));
    }

    if(properties.containsKey("jobId")) {
        request.addProperty("jobId", properties.getInt("jobId"));
        System.out.println("jobId = " + properties.getInt("jobId"));
    }

    if(properties.containsKey("laborDetailId")) {
        request.addProperty("laborDetailId", properties.getInt("laborDetailId"));
        System.out.println("laborDetailId = " + properties.getInt("laborDetailId"));
    }

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SOAP_VERSION);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);

    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL, timeout);       

    androidHttpTransport.call(action, envelope);
    Object result = envelope.getResponse();
    String resultData = "null response";
    if(result != null) {
        resultData = result.toString();
    }

    System.out.println("Result for web method " + method + ": " + resultData);

    return resultData;
}
于 2013-07-29T17:37:09.227 回答