java - Zipping InputStream, returning InputStream (in memory, no file)

Question

I am trying to do compress an InputStream and return an InputStream:

public InputStream compress (InputStream in){
  // Read "in" and write to ZipOutputStream
  // Convert ZipOutputStream into InputStream and return
}

I am compressing one file (so I could use GZIP) but will do more in future (so I opted for ZIP). In most of the places:

• Compress an InputStream with gzip

• How can I convert ZipInputStream to InputStream?

  They use toBytesArray() or getBytes() which do not exist (!) - ZipOutputStream

My problems are:

1. How do I convert the ZipOutPutStream into InputStream if such methods don't exist?

2. When creating the ZipOutPutStream() there is no default constructor. Should I create a new ZipOutputStrem(new OutputStream() ) ??

Answer 1

像这样的东西：

private InputStream compress(InputStream in, String entryName) throws IOException {
        final int BUFFER = 2048;
        byte buffer[] = new byte[BUFFER];
        ByteArrayOutputStream out = new ByteArrayOutputStream();
        ZipOutputStream zos = new ZipOutputStream(out);
        zos.putNextEntry(new ZipEntry(entryName));
        int length;
        while ((length = in.read(buffer)) >= 0) {
            zos.write(buffer, 0, length);
        }
        zos.closeEntry();
        zos.close();
        return new ByteArrayInputStream(out.toByteArray());
}

Answer 2

1. 使用具有 .toByteArray() 的 ByteArrayOutputStream 解决它
2. 同样在这里，传递上述元素