unit-testing - 在 basemodel 中进行验证的 laravel 可测试存储方法

Question

但是，我正在尝试测试创建追随者，因为我正在调用 Auth::user()->id 我收到错误“尝试获取非对象的属性”。目前我一直在构建一个输入数组，当我运行 create 方法时，验证是从 BaseModel 中的引导方法触发的。有没有办法我应该模拟 $input 数组，或者我应该在我的存储库的 create 方法中进行验证？

<?php

class FollowersTest extends TestCase {

public function setUp()
{
  parent::setUp();

  $this->mock = $this->mock('Convoconnect\Storage\Follower\FollowerRepository');
}

public function mock($class)
{
  $mock = Mockery::mock($class);

  $this->app->instance($class, $mock);

  return $mock;
}

public function tearDown()
{
  Mockery::close();
}

/**
 * Test Store success
 */
public function testStoreSuccess()
{
  $input = [
    'user_id' => 1,
    'follower_id' => 4,
  ];

    $this->mock
        ->shouldReceive('create')
        ->once();

  $this->call('POST', 'followers', $input);

  $this->assertRedirectedToRoute('followers.index');
 }
}



<?php

use Convoconnect\Storage\Follower\FollowerRepository as Follower;

class FollowersController extends BaseController {

/**
* Follower Repository
*
* @var Follower
*/
protected $follower;

public function __construct(Follower $follower) {
    $this->follower = $follower;
}

public function store() {

    $input = [
        'user_id' => Auth::user()->id,
        'follower_id' => Input::get('follower_id'),
    ];

    $follower = $this->follower->create($input);

    if($follower->save()) return Redirect::route('followers.index');

    return Redirect::back()
        ->withInput()
        ->withErrors($follower->errors);
 }
}   

Answer 1

你可以嘲笑这种Validator行为：

Validator::shouldReceive('make')
    ->once()
    ->andReturn(Mockery::mock(array('fails' => true)));

在这篇 Nettuts 文章中有很多关于测试控制器的有用信息。Jeffrey Way 的书Laravel Testing Decoded也很值得一看。