php - php 调用非对象上的成员函数

Question

最后一行回显不起作用。我如何引用 id 或昵称？我收到的错误是 Call to a member function on a non-object in. dsaojfj kjsaoj oisjao jpods jop djopa jpaos jdo jpoajsoj op pa poj opdjaojs pojap jposajop jopajojdopsajodjop jaop jpoj ojdojpsoaj ojod jopajsdodjaospjop d add details ....srr。

<?php
class  test{

    public $id;
    public $nickname;

    function __construct($id_, $nickname_) {
        $this->id = $id_;
        $this->nickname = $nickname_;
    }

    public function setId($id_){
       $this->id = $id_;
    }
    public function setNickname($nickname_){
       $this->nickname = $nickname_;
    }
    public function getId(){
       return $this->id;
    }
    public function getNickname(){
       return $this->nickname;
    }
}

class  InfoTest{

    public $tests = array();
    public $number;

    function __construct() {
       $this->number = 0;
    }

    public function addTest(test $test_){
        $this->number++;
        $this->tests[$number] = $test_;
    }

    public function numberTests(){
        return $this->number;
    }

}


$r = new test(1,2);
$cc = new InfoTest;
$cc->addTest($r);
echo $cc->tests[1]->getId();

?>

Answer 1

您在第二次使用数字变量时忘记了 $this->：

    $this->number++;
    $this->tests[$number] = $test_;

应该

    $this->number++;
    $this->tests[$this->number] = $test_;