javascript - Declare function twice for closure?

Question

I've got something like this:

// This executes once when the page loads.
(function() {
    //under some conditions, it calls:
    myfunction();

    function myFunction() {  
        // defines function
    }
}());

function thisIsCalledByAnOnClick() {
    // HERE I need to call myFunction()
}

I dont want myFunction() to be called from the console, so I enclosed it inside the anonymous function. So, If I need to call it somewhere else, do I declare it twice or what do I do?

Answer 1

在闭包thisIsCalledByAnOnClick内可以访问myFunction. 有关详细信息，请参阅：模块模式。

// This executes once when the page loads.
var modul = function() {
    //under some conditions, it calls:
    myfunction();

    function myFunction() {
        // defines function
    }

    return {
        thisIsCalledByAnOnClick : function() {
        // HERE I need to call myFunction()
        }
    };
}();

Answer 2

1. 在匿名函数中定义 thisIsCalledByAnOnclick()。
2. 使用 addEventListener 分配 onClick 句柄。

Answer 3

您可以使用构造函数来封装这两个函数。一个作为公共功能，另一个作为私人功能。

D.

Answer 4

function() {
     xyz = function() {
           return this;
           };

     xyz.prototype= {

     Myfunction1 : function(param1,param2)  {
     //some code!!!
     },
     Myfunction2 : function(param1,param2) {
     //some code!!!
     }
     };
})();

function thisIsCalledByAnOnClick() {

        instance=new xyz();
        instance.Myfunction1(a,b)
}