0

我似乎无法在 ActionListener 中更改 JButton ActionCommand。我试图通过更改 ActionCommand 多次使用相同的两个按钮,但这似乎不起作用。这是我的代码,希望对您有所帮助:

void ChangeAction() {
    storyButn1.setActionCommand("but3");
    storyButn2.setActionCommand("but4");
}

public Main() {

    story.setText("<html>You wake up with a sore head in a dark forest. You can't remember anything, except from the word H.E.L.P. You see a light in the distance, What to do? </html>");

    storyButn1.addActionListener(this);
    storyButn1.setActionCommand("but1");

    storyButn2.addActionListener(this);
    storyButn2.setActionCommand("but2");

    Box Layout = new Box(BoxLayout.Y_AXIS);
    Layout.add(story);
    Layout.setSize(story.getWidth() + 10, story.getHeight());

    frame.setVisible(true);
    frame.setSize(400, 200);
    frame.setDefaultCloseOperation(EXIT_ON_CLOSE);
    frame.add(Layout, BorderLayout.CENTER);
    frame.add(storyButn1);
    frame.add(storyButn2);
    frame.setTitle("Text Adventure");

    frame.setLayout(new GridLayout(3, 2, 5, 5));
    frame.getContentPane().setBackground(Color.lightGray);

}

public void actionPerformed(ActionEvent e) {
    if (e.getActionCommand().equals("but1")) {
        random = (int) (Math.round(Math.random()) * 10);
        if (random == 10) {
            story.setText("<html>You run towards the light source. It's dark and you don't see that root in the ground. You break your ankle!</html>");
            storyButn1
                    .setText("<html>Lay against a tree and hope for the best?</html>");
            storyButn2.setText("<html>Call out for help?</html>");
        } else {
            story.setText("<html>You walk carefully towards the light source, When you reach it, you find that it is a torch.</html>");
            storyButn1.setText("Pick it up?");
            storyButn2.setText("Switch it off?");
        }
    }
    if (e.getActionCommand().equals("but2")) {
        random = (int) (Math.round(Math.random()) * 20);
        if (random == 20) {
            story.setText("<html>You are near the top of the tree when your foot slips. You go plummeting back into the darkness, never to be seen again.");
            storyButn1.setText("Retry?");
            storyButn2.setText("Retry?");
            if (e.getActionCommand().equals("but1") || e.getActionCommand().equals("but2")) {
                this.dispose();
                frame.setVisible(false);
                new Main();             
            }
        } else {
            story.setText("<html>You successfully climb to the top of the tree where you find a safe spot to sit. You stay there for a while, *BANG*, You hear something in the distance!</html>");
            ChangeAction();
            storyButn1.setText("Climb down and investigate?");
            storyButn2.setText("Follow the light source?");

                if(e.getActionCommand().equals("but3")){
                    story.setText("<html>You slowly climb down the tree. When you reach the bottom, you try to follow where you think the sound had come from. As your walking you look down. There is a loaded revolver with one bullet missing and a trail of blood.</html>");
                } else if(e.getActionCommand().equals("but4")){
                    story.setText("<html>You walk carefully towards the light source, When you reach it, you find that it is a torch.</html>");
                }
        }
    }

}
4

2 回答 2

2

"but3"如果操作命令是or ,则只有一个地方可以做某事"but4",并且该地方位于以下 if 块内:

if (e.getActionCommand().equals("but2")) {

显然,action 命令不可能同时是"but2"and "but3"or "but4"。这是一个或另一个。

因此,以下if块的条件将始终评估为false

if(e.getActionCommand().equals("but3")){
    story.setText("<html>You slowly climb down the tree. When you reach the bottom, you try to follow where you think the sound had come from. As your walking you look down. There is a loaded revolver with one bullet missing and a trail of blood.</html>");
} else if(e.getActionCommand().equals("but4")){
    story.setText("<html>You walk carefully towards the light source, When you reach it, you find that it is a torch.</html>");
}

编辑:

回顾一下,该actionPerformed()方法如下所示:

public void actionPerformed(ActionEvent e) {
    if (e.getActionCommand().equals("but1")) {
        // do something
    }
    if (e.getActionCommand().equals("but2")) {
        // do something
    }
}

它不处理动作命令是"but3"or的情况"but4"

于 2013-07-27T14:17:44.710 回答
0

你无法到达这部分代码

else {
        story.setText("<html>You successfully climb to the top of the tree where you find a safe spot to sit. You stay there for a while, *BANG*, You hear something in the distance!</html>");
        ChangeAction();
        storyButn1.setText("Climb down and investigate?");
        storyButn2.setText("Follow the light source?");
    }

在这里调用 ChangeAction()。测试使用system.out.println("inside else");你会看到这条线永远不会被打印出来。

您需要在第一个两个 if 语句中的某处使用 ChangeAction()

于 2013-07-27T14:34:02.610 回答