我尝试使用代码中的方法建立连接没有成功。以前我根据我的代码使用了 $con 变量。这建立了联系，一切似乎都很好。PS我所有的路径都是正确的。
<?php
$con = new dbmember();
$con->openDB();
//
// this WORKS but I want to use my function to do this for me instead
//$con=mysqli_connect("localhost","user","password","db_name");
//
$user=$_POST['user'];
$password=$_POST['password'];
if(isset($_POST['submit'])){
//To ensure that none of the fields are blank when submitting the form if
if(isset($_POST['user']) && isset($_POST['password']))
{
$user = stripslashes($user);
$password = stripslashes($password);
$user = mysqli_real_escape_string($con, $user);
$password = mysqli_real_escape_string($con, $password);
//SQL Injection Ahoy! I know...but future versions aim to be robust!
$sql="SELECT * FROM users WHERE username='users' and password='password'";
$result=mysqli_query($con, $sql);
$row=mysqli_fetch_array($result);
if($row[0]==1)
{
session_start();
$_SESSION['user'] = $user;
$_SESSION['password'] = $password;
$_SESSION['loggedin'] = "true";
header("location:index.php");
}
else
{
print ('<div id="error">Acess denied, wrong username or password?</div>');
}
}
else
{
print ('<div id="error">Enter something!</div>');
}
}
?>
这是我的方法
<?php
require("assets/configs/db_config.php");
class dbmember {
/* DB connection handle */
var $conn;
function openDB() {
// 1. Create a database connection
$conn = mysqli_connect("localhost" , "username", "password","db_name");
if (!$conn)
{
$this->error_msg = "connection error could not connect to the database:! ";
return false;
给出的错误：
Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\c\login.php on line 98
Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\c\login.php on line 99
Warning: mysqli_query() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\c\login.php on line 104
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in C:\xampp\htdocs\c\login.php on line 106
我只能假设 $con 不能正确传递。你能提供一个解决方案吗？