我使用这段代码：
<?php
// Get values from form
$name= mysql_real_escape_string($_POST['name']);
if (empty($name)) {
echo "No information has entered";
echo "<br/>";
echo "<br/>";
echo "<a href='index.php'>Return to Homepage</a>";
exit;
}
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="pin"; // Database name
$tbl_name="test"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// Insert data into mysql
$sql = "UPDATE $tbl_name SET `Used` = '1' WHERE `test`.`Code` =$name;";
//echo $sql; exit;
$result=mysql_query($sql);
// if successfully insert data into database, displays message "Successful".
if($result){
echo "Your Information </br>";
echo "<BR>";
echo "<a href='index.html'></a>";
$result = mysql_query("SELECT Code FROM `test` WHERE `Code` =$name" );
while ($row = mysql_fetch_array($result)) {
printf("Code: %s </br>", $row[0]);
$foundcode=$row[0];
}
if (!empty($foundcode)) {
echo "<BR>";
echo "<a href='".$foundcode.".pdf'>Click here to download.</a>";
}
if (empty($foundcode)){
echo "<BR>";
echo "Password is wrong";
}
mysql_free_result($result);
echo "<BR>";
echo "<BR>";
echo "<BR>";
echo "<a href='index.php'>Exit</a>";
}
else {
echo nl2br ("Entered Information are not valid, Please enter valid information </br></br>");
echo "<a href='index.php'>Return to Homepage</a></br></br>";
}
// close connection
mysql_close();
?>
但我收到此错误：
Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'root'@'localhost' (using password: NO)
我阅读了一些帮助，但我无法修复它。我读了一些关于这个问题的答案，比如：
尽管我更改了数据库用户并通过了，但该问题仍然存在。