mysql - 如何从具有多个相似组合的 MySQL 数据库中获取行？

Question

我需要从具有WHERE多种LIKE组合条件的表中获取行，

我的意思是，例如，我description在表中有一个字段，它有两行

1. 'abc def hij klm'
2. 'opq rst uvw xyz'

我的搜索文本是abc rst. 所以我需要一个LIKE条件必须产生两行的查询，因为第一行包含字符串abc，第二行包含rst。我知道我可以使用ORin between twoLIKE条件，但是如果搜索文本太长，因为它有更多的单词，我该怎么办？

Answer 1

This can be a bit painful, but one way to do it is with like and substring_index()

where concat(' ', description, ' ') like concat('% ', substring_index(@SearchString, ' ', 1), ' %') and
      concat(' ', description, ' ') like concat('% ', substring_index(substring_index(@SearchString, ' ', 2), ' ', -1), ' %') and 
      concat(' ', description, ' ') like concat('% ', substring_index(substring_index(@SearchString, ' ', 3), ' ', -1), ' %') and 
      concat(' ', description, ' ') like concat('% ', substring_index(substring_index(@SearchString, ' ', 4), ' ', -1), ' %')

The nested substring_index() return the nth item of the list.

If the codes you are looking for a real codes just glommed together in the description field, then you have bad database design. You need an association table with a single row for each code.

If the description is really a text description, then you might really want full text indexing. This would solve your problem using match . . . against.