3

这是一个 JavaScript 问题。

我需要创建一个按钮，单击该按钮将打开 5 个子窗口（弹出框）。

一个框将在屏幕的左上角，一个在右上角，一个在左下角，一个在右下角，一个在中间。每个框都有不同的 URL。

当主窗口关闭时，所有子窗口也应该关闭。

我只能编写打开一个弹出窗口的代码 - 无法弄清楚如何编写所有 5 个代码以通过单击一个按钮一次打开，然后在父窗口关闭时将它们全部关闭。

这是我到目前为止所拥有的：

<SCRIPT language="JavaScript">
function myPopup(URL) {
popupWindow = window.open(URL,'popUpWindow','height=500,width=500,left=100,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');
}
</SCRIPT>

<a href="#" onclick="myPopup(this.href);return false">Open Pop-Up</a>

非常感谢任何可以帮助我的人。

感谢所有帮助我的人。通过利用这里的反馈，我整天都在研究这个项目，并提出了一些有效的代码。我不确定如何将每个弹出窗口的 url 分配给数组 - 但至少它们有效。

但是，当父窗口关闭时，我无法关闭所有弹出窗口。希望你能帮忙。这是新代码：

<script type="text/javascript">

/*Use Array - Open 5 new popup windows using onclick*/

function newWindow() {
 var winPop = new Array();
  winPop[winPop.length] = window.open('top_right.html','window1','scrollbars=no,width=235,height=155,left=1000,top=200,screenX=1000,screenY=200');
window.open('top_left.html','window2','scrollbars=no,width=235,height=155,left=325,top=200,screenX=325,screenY=200');
window.open('bottom_left.html','window3','scrollbars=no,width=235,height=155,left=325,top=600,screenX=325,screenY=600');
window.open('bottom_right.html','window4','scrollbars=no,width=235,height=155,left=1000,top=600,screenX=1000,screenY=600');
window.open('center_page.html','window5','scrollbars=no,width=235,height=155,left=660,top=450,screenX=660,screenY=450');
}

/*NOT WORKING FOR ME --Close all popups when parent window is closed*/

onbeforeunload = function() {
    for (var index = 0; index < winPop.length; ++index)
        winPop[index].close();
}
</script>
</head>

<body>
<div id="wrap"> <a href='' onclick='newWindow()'><img src='images/group_clicker.gif' border='0'></a> </div>
</body>
4

3 回答 3

1

演示

将所有打开的窗口保存到一个数组中。
注册beforeUnload事件，当它触发时，循环遍历close()它们的弹出窗口。

注意：我认为它是 jsFiddle 或 Chrome，但每次点击它不会打开超过 1 个弹出窗口。

And due to restrictions placed on popup opening you cannot reliably control the position of opened popups. It may be useful for you to open in-window popups like YUI's panel or jQuery(UI)'s dialogue

function openPopup(howMany) {
    var popups = [];

    var temp;
    for (var index = 0; index < howMany; ++index) {
        popups.push(open('', '', 'height=500,width=500'));
        popups[index].document.write('popup ' + (index + 1) + ' of ' + howMany + '<br/>this will close on parent window close');
    }

    closeFunc = function() {
        for (var index = 0; index < popups.length; ++index)
            popups[index].close();
    };

    if (addEventListener)
        addEventListener('beforeunload', closeFunc, false);
    else
        attachEvent('onbeforeunload', closeFunc);
}
于 2013-07-27T11:07:54.407 回答
0

您可以使用 for 循环打开多个窗口。一定要给弹出窗口一个唯一的名字

function myPopup(URL) {
    for (var i = 0; i < 5; i++) {
        var popupWindow = window.open(URL, i, 'height=500,width=500,left=100,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');
    }
}
于 2013-07-27T07:44:57.927 回答
0

An answer to your edit:

You wrote

function newWindow() {
 var winPop = new Array();
  winPop[winPop.length] = window.open('top_right.html','window1','scrollbars=no,width=235,height=155,left=1000,top=200,screenX=1000,screenY=200');
window.open('top_left.html','window2','scrollbars=no,width=235,height=155,left=325,top=200,screenX=325,screenY=200');
window.open('bottom_left.html','window3','scrollbars=no,width=235,height=155,left=325,top=600,screenX=325,screenY=600');
window.open('bottom_right.html','window4','scrollbars=no,width=235,height=155,left=1000,top=600,screenX=1000,screenY=600');
window.open('center_page.html','window5','scrollbars=no,width=235,height=155,left=660,top=450,screenX=660,screenY=450');
}

What you need is

var winPop;

function newWindow() {
    winPop = [
        open(
            'top_right.html',
            'window1',
            'scrollbars=no,width=235,height=155,left=1000,top=200,screenX=1000,screenY=200'
        ),
        open(
            'top_left.html',
            'window2',
            'scrollbars=no,width=235,height=155,left=325,top=200,screenX=325,screenY=200'
        ),
        open(
            'bottom_left.html',
            'window3',
            'scrollbars=no,width=235,height=155,left=325,top=600,screenX=325,screenY=600'
        ),
        open(
            'bottom_right.html',
            'window4',
            'scrollbars=no,width=235,height=155,left=1000,top=600,screenX=1000,screenY=600'
        ),
        open(
            'center_page.html',
            'window5',
            'scrollbars=no,width=235,height=155,left=660,top=450,screenX=660,screenY=450'
        )
    ];
}

This is a scoping issue (as well as you not actually adding the windows to the array :|), winPop needs to be global, I.e. vard outside of the function.

于 2013-07-28T02:38:03.770 回答