0

因此，我有两个 if 语句来检测您使用的是 HTC 8X 还是 8S，通过手机提供的 DeviceName。问题是它似乎忽略了“If”并只运行所有代码......例如，我放置了一行代码（用于调试），一旦它运行每个部分就会显示一个消息框，但是两个消息框都显示了，而不仅仅是 8X，显示它正确检测到我正在 8X 上运行应用程序。这可能只是一个“愚蠢的错误”，但我无法弄清楚......

  if (Microsoft.Phone.Info.DeviceStatus.DeviceName == "Windows Phone 8X by HTC") ;
            {
                //Debugging MSG
                MessageBox.Show("8X Works")
                //Rating
                MainScore.Text = "6.1";
                //Subscores
                Processor.Text = "5.2";
                RAM.Text = "6.5";
                Graphics.Text = "8.0";
                HardDisk.Text = "5.1";
                //Issues
                Issues.Text = "0 ISSUES FOUND";
            }
            if (Microsoft.Phone.Info.DeviceStatus.DeviceName == "Windows Phone 8S by HTC");
            {
                //Debugging MSG
                MessageBox.Show("8S Works")
                //Rating
                MainScore.Text = "2.8";
                //Subscores
                Processor.Text = "3.2";
                RAM.Text = "2.4";
                Graphics.Text = "4.0";
                HardDisk.Text = "1.9";
                //Issues
                Issues.Text = "0 ISSUES FOUND";
            }
4

2 回答 2

8

每次 IF 测试后立即删除分号。分号后面的代码块每次都无条件运行。

于 2013-07-27T01:32:31.637 回答
1

由于分号，这是编译器如何看待您的代码。
（看/* */评论）

if (Microsoft.Phone.Info.DeviceStatus.DeviceName == "Windows Phone 8X by HTC")
    /* DO NOTHING */;

/* Regular, Unconditional Code */
{
    //Debugging MSG
    MessageBox.Show("8X Works")
    //Rating
    MainScore.Text = "6.1";
    //Subscores
    Processor.Text = "5.2";
    RAM.Text = "6.5";
    Graphics.Text = "8.0";
    HardDisk.Text = "5.1";
    //Issues
    Issues.Text = "0 ISSUES FOUND";
}

if (Microsoft.Phone.Info.DeviceStatus.DeviceName == "Windows Phone 8S by HTC")
    /* DO NOTHING */;

/* Regular Unconditional code */
{
   //Debugging MSG
   MessageBox.Show("8S Works")
   //Rating
   MainScore.Text = "2.8";
   //Subscores
   Processor.Text = "3.2";
   RAM.Text = "2.4";
   Graphics.Text = "4.0";
   HardDisk.Text = "1.9";
   //Issues
   Issues.Text = "0 ISSUES FOUND";
 }
于 2013-07-27T02:21:00.770 回答