0

我正在将数据从一个旧表一次性导入到 Wordpress 评论表中(因此开销不是问题)。我遍历旧表,使用 php 调整新表的一些数据,然后执行每个插入。它只会插入第一行。如果我再次运行代码,它将插入相同的第一行,所以我认为没有主键问题。

require('wp-config.php');

$con=mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME); 

$result = mysqli_query($con,"SELECT *
    FROM user_import u, wp_posts p, wp_postmeta m
    WHERE p.ID = m.post_id
    AND m.meta_key = 'fanfic_id'
    AND m.meta_value = u.fanfic_id");

while($row = mysqli_fetch_array($result))
  {
    $nick=$row['user_nickname'];
    $ip=$row['user_ip_address'];
    $date=strToTime($row['user_fanfic_date']);
    $date2=strftime('%Y-%m-%d 12:00:00',$date);
    $gmt=strftime('%Y-%m-%d 12:00:00', $date);
    $datemine = date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $date)));

    $fanfic_id=$row['fanfic_id'];

    $getPostID="SELECT post_id FROM wp_postmeta WHERE meta_key='fanfic_id' and meta_value=$fanfic_id";

    $result2 = mysqli_query($con,$getPostID );

    while($row2 = mysqli_fetch_array($result2)){
      $post_id=$row2['post_id'];

    }

    $review=$row['user_fanfic_review'];
    $sql="INSERT INTO wp_comments(comment_approved, user_id, comment_post_id, comment_author, comment_author_ip, comment_date, comment_date_gmt, comment_content)
      VALUES(1, 0, $post_id,'$nick','$ip', '$date2', '$gmt', '$review') ";

    $result = mysqli_query($con,$sql);

  }

mysqli_close($con);
4

2 回答 2

3

我相信因为这条线

$sql="INSERT INTO wp_comments(comment_approved, user_id, comment_post_id, comment_author, comment_author_ip, comment_date, comment_date_gmt, comment_content)
  VALUES(1, 0, $post_id,'$nick','$ip', '$date2', '$gmt', '$review') ";
$result = mysqli_query($con,$sql); // <--- this line.

由于您将$resultSELECT 的 重新分配给 INSERT 的结果。你能把那条线改成这个吗?

 mysqli_query($con,$sql);
于 2013-07-27T01:08:52.167 回答
0

此时存在问题:

$getPostID="SELECT post_id FROM wp_postmeta WHERE meta_key='fanfic_id' and meta_value=$fanfic_id";

$result2 = mysqli_query($con,$getPostID );

while($row2 = mysqli_fetch_array($result2)){
 $post_id=$row2['post_id'];
}

你所做的总是post_id在循环中得到相同的结果。这意味着每次第一个 while 循环while($row = mysqli_fetch_array($result))运行第二个 while 时都会获取相同的数据并继续插入操作。

PS 考虑使用$wpdb对象进行 wordpress 数据库操作http://codex.wordpress.org/Class_Reference/wpdb

于 2013-07-27T01:10:56.070 回答