1

我的应用程序中有一个 ImageView，我希望它在单击时打开某个网站。我很确定我做的一切都是正确的，但它仍然无法正常工作。一旦我单击 ImageView，应用程序就会崩溃。

ImageView banner = (ImageView)findViewById(R.id.banner);
banner.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            Intent openUrl = new Intent();
            openUrl.setAction(Intent.ACTION_VIEW);
            openUrl.addCategory(Intent.CATEGORY_BROWSABLE);
            openUrl.setData(Uri.parse("www.google.com"));
            startActivity(openUrl);
        }
    });

日志文件：

07-26 21:53:49.481: E/AndroidRuntime(25479): FATAL EXCEPTION: main
07-26 21:53:49.481: E/AndroidRuntime(25479): android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.VIEW cat=[android.intent.category.BROWSABLE] dat=www.google.com }
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.Instrumentation.checkStartActivityResult(Instrumentation.java:1622)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.Instrumentation.execStartActivity(Instrumentation.java:1417)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.Activity.startActivityForResult(Activity.java:3370)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.Activity.startActivityForResult(Activity.java:3331)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.Activity.startActivity(Activity.java:3566)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.Activity.startActivity(Activity.java:3534)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at si.dvanadva.evanturist.CheckpointsActivity$2.onClick(CheckpointsActivity.java:323)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.view.View.performClick(View.java:4204)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.view.View$PerformClick.run(View.java:17355)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.os.Handler.handleCallback(Handler.java:725)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.os.Handler.dispatchMessage(Handler.java:92)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.os.Looper.loop(Looper.java:137)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at android.app.ActivityThread.main(ActivityThread.java:5041)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at java.lang.reflect.Method.invokeNative(Native Method)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at java.lang.reflect.Method.invoke(Method.java:511)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:793)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:560)
07-26 21:53:49.481: E/AndroidRuntime(25479):    at dalvik.system.NativeStart.main(Native Method)
4

3 回答 3

1

您还需要确保您URL的格式正确（前缀很重要）：

http://www.google.com

不是

www.google.com

看看这篇文章的例子。

于 2013-07-26T19:59:42.600 回答
1

替换这个

  openUrl.setData(Uri.parse("www.google.com"));

经过

  openUrl.setData(Uri.parse("http://www.google.com"));

更多信息 @

http://developer.android.com/reference/android/content/Intent.html

编辑：

    String url = "www.google.com";
    if (!url.startsWith("http://") && !url.startsWith("https://"))
    {
         url = "http://" + url;
    }
    else
    {
    Intent openUrl = new Intent();
    openUrl.setAction(Intent.ACTION_VIEW);
    openUrl.addCategory(Intent.CATEGORY_BROWSABLE);
    openUrl.setData(Uri.parse(url));      
    startActivity(openUrl);
    }
于 2013-07-26T20:07:56.800 回答
0

您想在浏览器窗口中打开网站吗？如果是这样，请删除 CATEGORY。我很确定这仅适用于 WebViews。

于 2013-07-26T20:00:57.717 回答