0

您好我正在尝试向接受 POST 数据 $_POST['username'] 的基于 PHP 的服务器进行简单的 HTTP 发布。

public void sendMessage(View view){

    String result = "";

    Intent intent = new Intent(this, DisplayMessageActivity.class);
    EditText editText = (EditText) findViewById(R.id.edit_message);
    String message = editText.getText().toString();
    intent.putExtra(EXTRA_MESSAGE, message);

    Toast.makeText(
            getApplicationContext(),
            "Attempting to open second activity",
            Toast.LENGTH_LONG
    ).show();

    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("username","ghost"));

    InputStream is = null;

    // ATTEMPT HTTP POST
    try{
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://example.com/getuserbyuname");
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();
    }catch(Exception e){
            Log.e("log_tag", "Error in http connection (Reason: " + e.toString() + " )");
    }

然后服务器将返回一个 JSON 格式的消息，如下所示：

{"response":"404"}

我遇到了 android.os.NetworkOnMainThread 的问题。我知道这是因为我的例程试图从主 UI 线程中执行与网络相关的操作。

我确实试过这个：

public class AccountConnector extends AsyncTask <String, Integer, Long>{

@Override
protected Long doInBackground(String... params)
{
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("username","bond"));

    InputStream is = null;

    // ATTEMPT HTTP POST
    try{
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://example.com/getuserbyuname");
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();
    }catch(Exception e){
            Log.e("log_tag", "Error in http connection (Reason: " + e.toString() + " )");
    }
    return null;
}

...省略其余代码...

谁能指出我正确的方向？

4

2 回答 2

0

解决这个问题的正确方法是使用Android AsyncTask进行网络访问。

处理此问题的懒惰方法是检查：

StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
于 2013-07-26T11:40:41.583 回答
0

添加这个..

StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
             .permitAll().build();
StrictMode.setThreadPolicy(policy);

把它放在清单文件中

     <uses-permission android:name="android.permission.INTERNET"/>
于 2013-07-26T11:38:52.880 回答