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我真的在为某些事情苦苦挣扎，想知道是否有人可以抽出一些时间来看看这个代码块。

原始行如下所示： $home_collectionsx=get_home_page_promoted_collections();

这会带回所有提升到主页的项目并将它们显示在主页上。然而，我只是想使用相同的代码和数组函数拉入 1 个项目，为此目的，id 为 5，所以我认为添加=array(5)或(array (5))会起作用 - 但它没有。

我希望它是一些简单的东西，或者是我错过或写得不正确的东西。

<?php 
if(!hook("EditorsPick")):
/* ------------ Collections promoted to the home page ------------------- */
$home_collectionsx=get_home_page_promoted_collections (array(5));
foreach ($home_collectionsx as $home_collectionx)
{
?>
<div class="EditorsPick">
<div class="HomePanel"><div class="HomePanelINtopEditors">
<div class="HomePanelINtopHeader">Editors Pick</div>
<div class="HomePanelINtopText">This is the editors pick of Asset Space...</div>
<div class="EditorsPicImage"><div style="padding-top:<?php echo floor((155-$home_collectionx["thumb_height"])/2) ?>px; margin-top: -24px; margin-bottom: -15px;">
<a href="<?php echo $baseurl_short?>pages/search.php?search=!collection<?php echo   $home_collectionx["ref"] ?>" onClick="return CentralSpaceLoad(this,true);"><img     class="ImageBorder" src="<?php echo   get_resource_path($home_collectionx["home_page_image"],false,"thm",false) ?>" width="<?php echo $home_collectionx["thumb_width"] ?>" height="<?php echo $home_collectionx["thumb_height"] ?>" /></div>
</div></div>
</div>
</div>
</div>
<?php
}
endif; # end hook homefeaturedcol
?>

这是上面代码连接到的数据库本身的函数……</p> 

function get_home_page_promoted_collections()
{
return sql_query("select   collection.ref,collection.home_page_publish,collection.home_page_text,collection.home_page_image,resource.thumb_height,resource.thumb_width from collection left outer join resource on collection.home_page_image=resource.ref where collection.public=1 and collection.home_page_publish=1 order by collection.ref desc");
}

任何帮助将不胜感激:-)

非常感谢 Rich

4

1 回答 1

1

该函数不带参数：get_home_page_promoted_collections()

你想要这样的东西：

$home_collectionsx=get_home_page_promoted_collections(5);

和：

function get_home_page_promoted_collections($id=null)
{
    $filterClause = '';
    if(!is_null($id))
    {
        //to only return this id
        $filterClause = ' AND collection.ref = '.intval($id);
        //to get all but that id
        $filterClause = ' AND collection.ref != '.intval($id);
    }
    return sql_query("SELECT collection.ref,collection.home_page_publish,collection.home_page_text,collection.home_page_image,resource.thumb_height,resource.thumb_width FROM collection LEFT OUTER JOIN resource on collection.home_page_image=resource.ref WHERE collection.public=1 AND collection.home_page_publish=1".$filterClause." ORDER BY collection.ref DESC");
}
于 2013-07-26T08:43:41.570 回答