4

我知道我不久前发布了这个，但我想出了解决方案。我为一个名为 Roblox 的游戏编写了这段代码，但我只是在这里发布代码，以防遇到同样问题的其他人需要解决方案。无论如何，这是代码：

outputTime = true -- true: will print the current time to output window. false: won't print time
createVariable = true -- true: creates variables under game.Lighting. false: won't create variables

-----------------------------------------------------------------------------------------------
--DO NOT EDIT BELOW----------------------------------------------------------------------------
-----------------------------------------------------------------------------------------------

if(createVariable) then
    yearVar = Instance.new("IntValue", game.Lighting)
    yearVar.Name = "Year"
    yearVar.Value = 0
    monthVar = Instance.new("IntValue", game.Lighting)
    monthVar.Name = "Month"
    monthVar.Value = 0
    dayVar = Instance.new("IntValue", game.Lighting)
    dayVar.Name = "Day"
    dayVar.Value = 0
    hourVar = Instance.new("IntValue", game.Lighting)
    hourVar.Name = "Hour"
    hourVar.Value = 0
    minuteVar = Instance.new("IntValue", game.Lighting)
    minuteVar.Name = "Minute"
    minuteVar.Value = 0
    secondVar = Instance.new("IntValue", game.Lighting)
    secondVar.Name = "Second"
    secondVar.Value = 0
    dayOfWeek = Instance.new("StringValue", game.Lighting)
    dayOfWeek.Name = "DayOfWeek"
    dayOfWeek.Value = "Thursday"
end
function giveZero(data)
    if string.len(data) <= 1 then
        return "0" .. data
    else
        return data
    end
end
function hasDecimal(value)
    if not(value == math.floor(value)) then
        return true
    else
        return false
    end
end
function isLeapYear(year)
    if(not hasDecimal(year / 4)) then
        if(hasDecimal(year / 100)) then
            return true
        else
            if(not hasDecimal(year / 400)) then
                return true
            else
                return false
            end
        end
    else
        return false
    end
end
local eYear = 1970
local timeStampDayOfWeak = 5
local secondsInHour = 3600
local secondsInDay = 86400
local secondsInYear = 31536000
local secondsInLeapYear = 31622400
local monthWith28 = 2419200
local monthWith29 = 2505600
local monthWith30 = 2592000
local monthWith31 = 2678400
local monthsWith30 = {4, 6, 9, 11}
local monthsWith31 = {1, 3, 5, 7, 8, 10, 12}
local daysSinceEpoch = 0
local DOWAssociates = {"Tursday", "Friday", "Saturday", "Sunday", "Monday", "Tuesday", "Wednesday"}
while(true) do
    now = tick()
    year = 1970
    secs = 0
    daysSinceEpoch = 0
    while((secs + secondsInLeapYear) < now or (secs + secondsInYear) < now) do
        if(isLeapYear(year+1)) then
            if((secs + secondsInLeapYear) < now) then
                secs = secs + secondsInLeapYear
                year = year + 1
                daysSinceEpoch = daysSinceEpoch + 366
            end
        else
            if((secs + secondsInYear) < now) then
                secs = secs + secondsInYear
                year = year + 1
                daysSinceEpoch = daysSinceEpoch + 365
            end
        end
    end
    secondsRemaining = now - secs
    monthSecs = 0
    yearIsLeapYear = isLeapYear(year)
    month = 1 -- January
    while((monthSecs + monthWith28) < secondsRemaining or (monthSecs + monthWith30) < secondsRemaining or (monthSecs + monthWith31) < secondsRemaining) do
        if(month == 1) then
            if((monthSecs + monthWith31) < secondsRemaining) then
                month = 2
                monthSecs = monthSecs + monthWith31
                daysSinceEpoch = daysSinceEpoch + 31
            else
                break
            end
        end
        if(month == 2) then
            if(not yearIsLeapYear) then
                if((monthSecs + monthWith28) < secondsRemaining) then
                    month = 3
                    monthSecs = monthSecs + monthWith28
                    daysSinceEpoch = daysSinceEpoch + 28
                else
                    break
                end
            else
                if((monthSecs + monthWith29) < secondsRemaining) then
                    month = 3
                    monthSecs = monthSecs + monthWith29
                    daysSinceEpoch = daysSinceEpoch + 29
                else
                    break
                end
            end
        end
        if(month == 3) then
            if((monthSecs + monthWith31) < secondsRemaining) then
                month = 4
                monthSecs = monthSecs + monthWith31
                daysSinceEpoch = daysSinceEpoch + 31
            else
                break
            end
        end
        if(month == 4) then
            if((monthSecs + monthWith30) < secondsRemaining) then
                month = 5
                monthSecs = monthSecs + monthWith30
                daysSinceEpoch = daysSinceEpoch + 30
            else
                break           
            end
        end
        if(month == 5) then
            if((monthSecs + monthWith31) < secondsRemaining) then
                month = 6
                monthSecs = monthSecs + monthWith31
                daysSinceEpoch = daysSinceEpoch + 31
            else
                break
            end
        end
        if(month == 6) then
            if((monthSecs + monthWith30) < secondsRemaining) then
                month = 7
                monthSecs = monthSecs + monthWith30
                daysSinceEpoch = daysSinceEpoch + 30
            else
                break
            end
        end
        if(month == 7) then
            if((monthSecs + monthWith31) < secondsRemaining) then
                month = 8
                monthSecs = monthSecs + monthWith31
                daysSinceEpoch = daysSinceEpoch + 31
            else
                break
            end
        end
        if(month == 8) then
            if((monthSecs + monthWith31) < secondsRemaining) then
                month = 9
                monthSecs = monthSecs + monthWith31
                daysSinceEpoch = daysSinceEpoch + 31
            else
                break
            end
        end
        if(month == 9) then
            if((monthSecs + monthWith30) < secondsRemaining) then
                month = 10
                monthSecs = monthSecs + monthWith30
                daysSinceEpoch = daysSinceEpoch + 30
            else
                break
            end
        end
        if(month == 10) then
            if((monthSecs + monthWith31) < secondsRemaining) then
                month = 11
                monthSecs = monthSecs + monthWith31
                daysSinceEpoch = daysSinceEpoch + 31
            else
                break
            end
        end
        if(month == 11) then
            if((monthSecs + monthWith30) < secondsRemaining) then
                month = 12
                monthSecs = monthSecs + monthWith30
                daysSinceEpoch = daysSinceEpoch + 30
            else
                break
            end
        end
    end
    day = 1 -- 1st
    daySecs = 0
    daySecsRemaining = secondsRemaining - monthSecs
    while((daySecs + secondsInDay) < daySecsRemaining) do
        day = day + 1
        daySecs = daySecs + secondsInDay
        daysSinceEpoch = daysSinceEpoch + 1
    end
    hour = 0 -- Midnight
    hourSecs = 0
    hourSecsRemaining = daySecsRemaining - daySecs
    while((hourSecs + secondsInHour) < hourSecsRemaining) do
        hour = hour + 1
        hourSecs = hourSecs + secondsInHour
    end
    minute = 0 -- Midnight
    minuteSecs = 0
    minuteSecsRemaining = hourSecsRemaining - hourSecs
    while((minuteSecs + 60) < minuteSecsRemaining) do
        minute = minute + 1
        minuteSecs = minuteSecs + 60
    end
    second = math.floor(now % 60)
    year = giveZero(year)
    month = giveZero(month)
    day = giveZero(day)
    hour = giveZero(hour)
    minute = giveZero(minute)
    second = giveZero(second)
    remanderForDOW = daysSinceEpoch % 7
    DOW = DOWAssociates[remanderForDOW + 1]
    if(createVariable) then
        yearVar.Value = year
        monthVar.Value = month
        dayVar.Value = day
        hourVar.Value = hour
        minuteVar.Value = minute
        secondVar.Value = second
        dayOfWeek.Value = DOW
    end
    if(outputTime) then
        str = "Year: " .. year .. ", Month: " .. month .. ", Day: " .. day .. ", Hour: " .. hour .. ", Minute: " .. minute .. ", Second: ".. second .. ", Day of Week: " .. DOW
        print(str)
    end
    wait(1)
end

----ORIGINAL POST---- 除了Epoch 以来的秒数之外没有资源的情况下计算以下公式的公式是什么？

这是我需要的清单：

当年的当前月份 例如：7

每月的当前日期 例如：25

一周中的当前日期 例如：星期四（可以接受 1-7）

当前时间 例如：22

当前分钟例如：34

当前分秒：07

4

6 回答 6

9

这是一些改编自谷歌找到的一些 C 代码的 Lua 代码。它不处理时区或夏令时，因此输出指的是通用协调时间 (UTC)。

-- based on http://www.ethernut.de/api/gmtime_8c_source.html

local floor=math.floor

local DSEC=24*60*60 -- secs in a day
local YSEC=365*DSEC -- secs in a year
local LSEC=YSEC+DSEC    -- secs in a leap year
local FSEC=4*YSEC+DSEC  -- secs in a 4-year interval
local BASE_DOW=4    -- 1970-01-01 was a Thursday
local BASE_YEAR=1970    -- 1970 is the base year

local _days={
    -1, 30, 58, 89, 119, 150, 180, 211, 242, 272, 303, 333, 364
}
local _lpdays={}
for i=1,2  do _lpdays[i]=_days[i]   end
for i=3,13 do _lpdays[i]=_days[i]+1 end

function gmtime(t)
print(os.date("!\n%c\t%j",t),t)
    local y,j,m,d,w,h,n,s
    local mdays=_days
    s=t
    -- First calculate the number of four-year-interval, so calculation
    -- of leap year will be simple. Btw, because 2000 IS a leap year and
    -- 2100 is out of range, this formula is so simple.
    y=floor(s/FSEC)
    s=s-y*FSEC
    y=y*4+BASE_YEAR         -- 1970, 1974, 1978, ...
    if s>=YSEC then
        y=y+1           -- 1971, 1975, 1979,...
        s=s-YSEC
        if s>=YSEC then
            y=y+1       -- 1972, 1976, 1980,... (leap years!)
            s=s-YSEC
            if s>=LSEC then
                y=y+1   -- 1971, 1975, 1979,...
                s=s-LSEC
            else        -- leap year
                mdays=_lpdays
            end
        end
    end
    j=floor(s/DSEC)
    s=s-j*DSEC
    local m=1
    while mdays[m]<j do m=m+1 end
    m=m-1
    local d=j-mdays[m]
    -- Calculate day of week. Sunday is 0
    w=(floor(t/DSEC)+BASE_DOW)%7
    -- Calculate the time of day from the remaining seconds
    h=floor(s/3600)
    s=s-h*3600
    n=floor(s/60)
    s=s-n*60
    print("y","j","m","d","w","h","n","s")
    print(y,j+1,m,d,w,h,n,s)
end

local t=os.time()
gmtime(t)

t=os.time{year=1970, month=1, day=1, hour=0} gmtime(t)
t=os.time{year=1970, month=1, day=3, hour=0} gmtime(t)
t=os.time{year=1970, month=1, day=2, hour=23-3, min=59, sec=59} gmtime(t)
于 2013-07-26T19:32:22.927 回答
3

由于几个原因，这个公式并不简单，尤其是闰年。您可能应该使用此页面date上的函数，而不是尝试自己计算。

于 2013-07-26T04:41:27.037 回答
2

你可以使用luatz

x = 1234567890
t = require "luatz.timetable".new_from_timestamp ( x )

print(t.year,t.month,t.day,t.hour,t.min,t.sec,t.yday,t.wday)
-- Or just
print(t:rfc_3339())
于 2013-08-06T00:36:49.067 回答
1

一个更快的解决方案是使用我的方法，我还没有真正看到其他人使用过，因为大多数人都可以访问 os.date()

由于我无权访问 os.date()，因此这是我的解决方案：

local tabIndexOverflow = function(seed, table)
    -- This subtracts values from the table from seed until an overflow
    -- This can be used for probability :D
    for i = 1, #table do
        if seed - table[i] <= 0 then
            return i, seed
        end
        seed = seed - table[i]
    end
end

local getDate = function(unix)
    -- Given unix date, return string date
    assert(unix == nil or type(unix) == "number" or unix:find("/Date%((%d+)"), "Please input a valid number to \"getDate\"")
    local unix = (type(unix) == "string" and unix:match("/Date%((%d+)") / 1000 or unix or os.time()) -- This is for a certain JSON compatability. It works the same even if you don't need it

    local dayCount, year, days, month = function(yr) return (yr % 4 == 0 and (yr % 100 ~= 0 or yr % 400 == 0)) and 366 or 365 end, 1970, math.ceil(unix/86400)

    while days >= dayCount(year) do days = days - dayCount(year) year = year + 1 end -- Calculate year and days into that year

    month, days = tabIndexOverflow(days, {31,(dayCount(year) == 366 and 29 or 28),31,30,31,30,31,31,30,31,30,31}) -- Subtract from days to find current month and leftover days

--  hours = hours > 12 and hours - 12 or hours == 0 and 12 or hours -- Change to proper am or pm time
--  local period = hours > 12 and "pm" or "am"

--  Formats for you!
--  string.format("%d/%d/%04d", month, days, year) 
--  string.format("%02d:%02d:%02d %s", hours, minutes, seconds, period)
    return {Month = month, day = days, year = year, hours = math.floor(unix / 3600 % 24), minutes = math.floor(unix / 60 % 60), seconds = math.floor(unix % 60)}
end

但是，在查找星期几时，您只能靠自己。我从不在乎是托尔的日子还是弗里格的日子。

于 2015-12-18T09:15:52.053 回答
0

os.date是一个标准的 Lua 函数，如果将第一个参数作为 传递"%t"，它将返回一个包含以下字段的表：（year四位），month（1--12），day（1--31），hour（0--23），min（ 0--59), sec(0--61), wday(weekday, Sunday is 1), yday(day of year), and isdst(daylight Saving flag, a boolean)。

给它一个测试：

time = os.time()
print("time since epoch: " .. time)
date = os.date("*t", time)
print("year: " .. date.year)
print("month: " .. date.month)
print("day: " .. date.day)
print("hour: " .. date.hour)
print("minute: " .. date.min)
print("second: " .. date.sec)
print("weekday: " .. date.wday)

输出：

time since epoch: 1374826427
year: 2013
month: 7
day: 26
hour: 16
minute: 13
second: 47
weekday: 6
于 2013-07-26T08:14:19.630 回答
0

我就是这样做的。

> time0=os.time()
> time0
1571439964
> os.date("%Y%m%d%H%M%S",time0)
20191019120604
>
于 2019-10-18T23:07:35.740 回答