2

根据App Engine 文档中的祖先查询,我可以执行以下操作:

type Team struct {
    Name string
}

type Player struct {
    Name string
}

// Save data first just for the test case
teamA := datastore.NewIncompleteKey(c, "Team", nil)
teamA, _ = datastore.Put(c, teamA, Team{"Team A"})
playerA := datastore.NewIncompleteKey(c, "Player", teamA)
playerA, _ = datastore.Put(c, playerA, Player{"Player A"})
playerB := datastore.NewIncompleteKey(c, "Player", teamA)
playerB , _ = datastore.Put(c, playerB, Player{"Player B"})

// query data
q := datastore.NewQuery("Team").Filter("Name=", "Team A").Limit(1).KeysOnly()
teams, _ := q.GetAll(c, nil)
q = datastore.NewQuery("Player").Ancestor(teams[0])
var players []Player
q.GetAll(c, &players)

但是...如果我想让 Team 包含一个指向玩家切片的指针,那么我会将它保存为 nil,当我查询它时,我会分配它,有点像这样:

type Team struct {
    Name string
    Players *[]Player `datastore:-`
}

type Player {
    Name string
}

// Save data first just for the test case
teamA := datastore.NewIncompleteKey(c, "Team", nil)
teamA, _ = datastore.Put(c, teamA, Team{"Team A", nil})

/* Saving player data goes here */

// query data
q := datastore.NewQuery("Team").Filter("Name=", "Team A").Limit(1)
var teams []Team
teamKeys, _ := q.GetAll(c, teams)
q = datastore.NewQuery("Player").Ancestor(teamKeys[0])
q.GetAll(c, teams[0].Players)

这是模拟关系的好方法吗?
对于我的应用程序,树形结构将是完美契合我手指的戒指。
或者……您还有其他建议吗?

4

1 回答 1

2
于 2013-08-20T08:22:03.910 回答