我在同一个视图中有两个按钮,一个正在处理要在另一个视图的标签中显示的数据,我已经为 button2 编写了函数(添加另一个值),当我单击 button2 时,它没有显示数据在视图中......而不是它给出这样的错误...... http:404资源未找到错误
这就是视图
@model MvcSampleApplication.Models.products
@{
ViewBag.Title = "Valuesadd";
}
<h2>Valuesadd</h2>
@using (Html.BeginForm("SubmitValue","EnterValue",FormMethod.Post))
{
<div>
<fieldset>
<legend>Enter Textbox Value</legend>
<div class ="editor-label">
@Html.LabelFor(m => m.EnteredValue)
</div>
<div class="editor-field">
@Html.TextBoxFor(m=>m.EnteredValue)
</div>
<p>
<input type="submit" value="Submit1" />
</p>
</fieldset>
</div>
}
@using (Html.BeginForm("SubmitValue2","EnterValue",FormMethod.Post))
{
<p>
<input type="submit" value="Submit2" />
</p>
}
这是控制器
namespace MvcSampleApplication.Controllers
{
public class EnterValueController : Controller
{
[HttpPost]
public ActionResult SubmitValue(MvcSampleApplication.Models.products model)
{
TempData["logindata"] = model.EnteredValue;
return RedirectToAction("submittedvalues" , "SubmitValue2");
// how can we redirect to another view when the button is clicked in one view
}
public ActionResult submittedvalues()
{
var model = new MvcSampleApplication.Models.category();
string data = TempData["logindata"] != null ? TempData["logindata"].ToString() : "";
model.lablvalue = data;
return View(model);
}
// action for second button click
public ActionResult submittedvalues2()
{
var model = new MvcSampleApplication.Models.category();
string data = TempData["logindata"] != null ? TempData["logindata"].ToString() : "";
model.lablvalue = "HIIII"+data;
return View(model);
}
}
}
你能提出任何想法吗..非常感谢...