0

需要复制然后重命名文件的副本，如果它已经存在

$pastaTemp = $_FILES['imagem_principal']['tmp_name'];
$pastaUpload = $_SERVER['DOCUMENT_ROOT']."/casaunica/imagens/acabamentos/";
$arquivo = $pastaUpload . $_FILES['imagem_principal']['name']; //filename.jpg

if(!file_exists($pastaUpload. $_FILES['imagem_principal']['name'])){
      $arquivo = $pastaUpload . $_FILES['imagem_principal']['name'];
} else {
    $nome_arquivo = explode(".",$_FILES['imagem_principal']['name']);
       do {
          $para = $nome_arquivo[0]."_".$i.".".$nome_arquivo[1];
          $nome_novo = rename($arquivo, $pastaUpload . $para);
          $arquivo = $pastaUpload .$nome_novo;
          $i++; 
       } while(file_exists($pastaUpload.$_FILES['imagem_principal']['name']));
}

输出：文件名.jpg_1

它应该是：filename_2.jpg

它不能替换旧文件..这就是为什么我需要用一个数字重命名它不需要在循环中进行但每次上传文件时

4

1 回答 1

1

试试这个代码，让我知道它是否有效

功能

<?php
  function recursive_naming( $file, $i = 1 ) {
    $dirname    = dirname( $file ).DIRECTORY_SEPARATOR;
    $filename   = pathinfo( $file, PATHINFO_FILENAME );
    $extension  = pathinfo( $file, PATHINFO_EXTENSION );

    if ( !file_exists( $file ) ) {
      return $file;
    }
    $filename = preg_replace( '/_\d+$/', '', $filename );
    $file = $dirname.$filename."_".$i.".".$extension;
    $i++;
    return recursive_naming( $file, $i );
  }
?>

例子：

<?php
  $pastaTemp    = $_FILES['imagem_principal']['tmp_name'];
  $pastaUpload  = $_SERVER['DOCUMENT_ROOT']."/casaunica/imagens/acabamentos/";
  $arquivo      = recursive_naming( $pastaUpload.$_FILES['imagem_principal']['name'] );
?>

它会输出filename_2.jpg如果filename.jpg存在，或者filename_3.jpg如果filename_2.jpg也存在，等等......

于 2013-07-24T18:19:03.490 回答