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The project is a web calendar/scheduler using php. The idea is that a user can schedule a job that is assigned to specific machine at a specific time and others can see the job schedule and which 'asset' the job is assigned to. The scheduling works, however, I cannot tie the data to header/columns they belong to. It looks like this:

 <?php
include_once("HTML/TABLE.PHP");
$data = array(  0=>array(1,'asset1','2013-07-24 10:00:00', '2013-07-24 12:00:00','red',2),
                1=>array(2,'asset1','2013-07-24 12:00:00', '2013-07-24 13:00:00','green',3),
                2=>array(3,'asset2','2013-07-24 11:00:00', '2013-07-24 12:00:00','blue', 4),
                3=>array(4,'asset2','2013-07-24 12:00:00', '2013-07-24 14:00:00','red', 2),
                4=>array(5,'asset3','2013-07-24 11:30:00', '2013-07-24 12:00:00','green', 4),
                5=>array(6,'asset4','2013-07-24 12:00:00', '2013-07-24 14:00:00','blue', 3),
                6=>array(7,'asset1','2013-07-24 11:45:00', '2013-07-24 13:00:00','red', 1),
                7=>array(8,'asset4','2013-07-24 13:00:00', '2013-07-24 15:00:00','yellow', 5)
              );
    $attrs = array( 'class' => 'main', 
        'id' => 'main_id',
        'width' => '100%',
        'border' => '1',
        'cellspacing' => '0',
        'cellpadding' => '0');
    $table = new HTML_Table($attrs);
    $table->setAutoGrow(true);
    $table->setAutoFill('n/a');

    $heads = array( array('asset1','asset2','asset3','asset4'));
        $i = 1;
    foreach($heads as $val)
    {
        $table->setHeaderContents(0, $i++, $val);
        unset($val);
    }   

    $now = date('U');
    $offset = ($now % 900);
    $now = $now-$offset;
    for ($i = 0;$i < 33; $i++)
    {
        $table->setHeaderContents($i,0, date('g:i',$now));
        $now += 900;
    }

    $cellPosition = 1;
    $rowCounter = 1;

    for ($i=0;$i < count($data);$i++)
    {
        $table->setCellAttributes ($rowCounter,$cellPosition,' bgcolor = '. $data[$i][4].  ' rowspan=' . $data[$i][5]);
        $table->setCellContents($rowCounter,$cellPosition,"Job# ".$data[$i][0] . " belongs to: " . $data[$i][1]);
            $cellPosition++;
            $rowCounter =1;
    }
    echo $table->display();
?>

How can I tie the information to only the column it belongs to?

I have gotten this far, but I get odd results if the first column is true:

$cellPosition = 0;
$rowCounter = 1;
for ($x=0;$x <= count($heads);$x++)
{
    for ($i=0;$i < count($data);$i++)
    {
        if ($data[$i][1] == $table->getCellContents(0,$x))
        {
        $table->setCellAttributes ($rowCounter,$cellPosition,' bgcolor = '. $data[$i][4].  ' rowspan=' . $data[$i][5]);
        $table->setCellContents($rowCounter,$cellPosition,"Job# ".$data[$i][0] . " belongs to: " . $data[$i][1]);
            //$cellPosition++;
            //echo ;
            echo "<br> The current count of x = : ".  $x;
            echo "<br>" . $table->getCellContents(0,$x) . " Matches " . $table->getCellContents(0,$x) . " at index " . $i;
            $rowCounter += $data[$i][5];
        }
            else
            {
                $rowCounter = 1;
            }

    }
    $cellPosition++;
4

1 回答 1

1

好的，这是可行的，但前提是数组结果按资产排序。如果不是，则将该行重置为第 1 行，并且第二个条目覆盖前一个条目。

$cellPosition = 0;
$rowCounter = 1;
for ($x=0;$x <= count($heads);$x++)
{
    for ($i=0;$i < count($data);$i++)
    {
        if ($data[$i][1] == $table->getCellContents(0,$x))
        {
        $table->setCellAttributes ($rowCounter,$cellPosition,' bgcolor = '. $data[$i][4].  ' rowspan=' . $data[$i][5]);
        $table->setCellContents($rowCounter,$cellPosition,"Job# ".$data[$i][0] . " belongs to: " . $data[$i][1]);
            echo "<br> The current count of x = : ".  $x;
            echo "<br>" . $table->getCellContents(0,$x) . " Matches " . $data[$i][1] . " at index " . $i;
            $rowCounter += $data[$i][5];
        }
            else
            {
                $rowCounter = 1;
            }

    }
    $cellPosition++;
}

我的解决方案是使用 sql order by 对记录进行预排序。我不知道这有多优雅，但目前它正在工作，我可以进一步进入这个项目。欢迎大家提出意见。谢谢！

于 2013-07-25T17:13:33.993 回答