问题
如果值不为 NULL,我想在最新日期显示以前的日期记录。我尝试了几件事,但没有真正奏效。下面是代码,实际和期望的结果。
从逻辑上讲,我想复制过去的日期值并将它们分配给最新的日期。任何帮助都会很棒。提前致谢!!
代码
$date = date('m/d/Y',time()+( 1 - date('w'))*24*3600);
$ts = strtotime($date);
$year1 = date('o', $ts);
$week = date('W', $ts);
$date_time_array1 = '';
for($i = 1; $i <= 7; $i++) {
$ts = strtotime($year1.'W'.$week.$i);
$date_time_array1[] = date('d/m/Y', $ts);
}//end for week dates
$gadget_data_type_date1 = array();
$empty = true;
for($i=0;$i<count($date_time_array1);$i++){
$flag = 0;
for($j=0;$j<count($date_time_array);$j++){
if($date_time_array1[$i] == $date_time_array[$j]){
$gadget_data_type_date1[] = $date_time_array1[$i];
$gadget_data_type_value1[] = $gadget_data_type_value[$j];
$flag =1;
}
}
if(!$flag){
$gadget_data_type_date1[] = $date_time_array1[$i];
}
$date_time = $gadget_data_type_date1[$i];
$t = explode("/",$date_time);
if (mktime(0,0,0,$t[1],$t[0],$t[2]) >= $game_starts_on) {
$date1 = date('m/d/Y',strtotime(str_replace("/",".",".$date_time.")));
$dateOneMonthSubtracted = date('n/j/Y', strtotime($date1));
$date_time_parse = "'".$dateOneMonthSubtracted.' UTC'."'";
if($gadget_data_type_value1[$i] != 'null'){
$gadget_data_type_value_value2[$i] = $gadget_data_type_value1[$i];
}else{
$gadget_data_type_value_value2[$i] = 'null';
}//end if check null
if ($gadget_data_type_value_value2[$i] != 'null' && $gadget_data_type_value_value2[$i] != '') {
$empty = false;
}//end if value is blank
$date_time_array2[] = "[Date.parse(".$date_time_parse."), ".$gadget_data_type_value_value2[$i]." ]";
}//end if current date is greater than start date
实际结果
[0] => [Date.parse('7/22/2013 UTC'), null ], i=>0
[1] => [Date.parse('7/23/2013 UTC'), 6.8717882122446 ], i=>1
[2] => [Date.parse('7/24/2013 UTC'), 0.3531183025553 ], i=>2
[3] => [Date.parse('7/24/2013 UTC'), 0.070564096031649 ], i=>3
[4] => [Date.parse('7/25/2013 UTC'), null ], i=>4
[5] => [Date.parse('7/26/2013 UTC'), 4.374864096031649 ], i=>5
[6] => [Date.parse('7/26/2013 UTC'), 1.263764096031649 ], i=>6
[7] => [Date.parse('7/27/2013 UTC'), null ], i=>7
期望的结果
[0] => [Date.parse('7/22/2013 UTC'), null ], i=>0
[1] => [Date.parse('7/23/2013 UTC'), 6.8717882122446 ], i=>1
[2] => [Date.parse('7/24/2013 UTC'), 6.8717882122446 ], i=>2
[3] => [Date.parse('7/24/2013 UTC'), 0.3531183025553 ], i=>3
[4] => [Date.parse('7/24/2013 UTC'), 0.070564096031649 ], i=>4
[5] => [Date.parse('7/25/2013 UTC'), null ], i=>5
[6] => [Date.parse('7/26/2013 UTC'), 6.8717882122446 ], i=>6
[7] => [Date.parse('7/26/2013 UTC'), 0.3531183025553 ], i=>7
[8] => [Date.parse('7/26/2013 UTC'), 0.070564096031649 ], i=>8
[9] => [Date.parse('7/26/2013 UTC'), 4.374864096031649 ], i=>9
[10] => [Date.parse('7/26/2013 UTC'), 1.263764096031649 ], i=>10
[11] => [Date.parse('7/27/2013 UTC'), null ], i=>11