因此,我使用 xPath 从 xml 文档中提取特定标签和元素并将其存储在一个对象中。我的问题是如何将此对象转换为字符串。我已经尝试过 .toString() 方法,但它给我的只是以下内容:
LocalHost 测试:org.apache.xml.dtm.ref.DTMNodeList@717e717e
我的代码如下:
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true); // never forget this!
DocumentBuilder builder = domFactory.newDocumentBuilder();
org.w3c.dom.Document doc = builder.parse("src/webSphere/testcases/positiveCode-data.xml");
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr
= xpath.compile(" /tests/class/method/params[@name='config']/param/text()");
MQQueueConnectionFactory cf = new MQQueueConnectionFactory();
Object result = expr.evaluate(doc, XPathConstants.NODESET);
System.out.println("LocalHost test: " + result.toString());
这是我的 xml 文件:
<?xml version ="1.0" encoding = "UTF-8"?>
<tests xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="http://jtestcase.sourceforge.net/dtd/jtestcase2.xsd">
<class name="Success">
<method name="success">
<test-case name="positive-code">
<params name="config">
<param name="hostName" type="java.lang.String">localhost</param>
<param name="port" type="int">7080</param>
<param name="transportType" type="java.lang.String">10</param>
<param name="queueManager" type="java.lang.String">MB8QMGR</param>
<param name="channel" type="java.lang.String">10</param>
<param name="inputQueue" type="java.lang.String">10</param>
<param name="outputQueue" type="java.lang.String">20</param>
<param name="testFile" type="java.lang.String">+</param>
<param name="expectedResultFile" type="java.lang.String">+</param>
</params>
<asserts>
<assert name="result" type="int" action="EQUALS">
30
</assert>
</asserts>
</test-case>
</method>
</class>
</tests>