所以，我有一个我一直在分支 A 中处理的文件，我正准备提交它。但是，查看差异，我认为最好将其放入两个单独的提交中（好吧，在这种情况下，可能是两个单独的分支）。我之前使用过 git add --patch 来分阶段，所以我想我可以使用它。问题是，我需要分裂我的一个帅哥。运行git add --patch SdA.py并使用e来编辑问题大块...
# Manual hunk edit mode -- see bottom for a quick guide
@@ -50,13 +50,74 @@ import PIL.Image as im
import constant
+
+def exp_range(min=None, max=None, step=None):
+ """
+ Generate an exponentially increasing value scaled and offset such
+ that it covers the range (min, max]. Behaviour is similar to
+ exp(x), scaled such that the final value generated is equal to
+ 'max'. 'step' defines the granularity of the exponential
+ function. The default value is 5, corresponding to a step-size
+ of tau.
+
+ :type min: float
+ :param min: minimum value of range (offset)
+
+ :type max: float
+ :param max: Maximum (final) value of range
+
+ :type step: int
+ :param step: Number of incremental steps within the range
+ (min, max]
+
+ """
+ if min is None:
+ raise StopIteration
+
+ # One input argument (same as range(10))
+ if min is not None and max is None and step is None:
+ step = min
+ min = 0.
+ max = 1.
+ elif step is None:
+ step = 5
+
+ for i in xrange(step):
+ exp_rate = np.exp(i - (step-1))
+ yield min + (max - min) * exp_rate
+ raise StopIteration
+
+
def norm(input):
+ """
+ Return the norm of a vector or row-wise norm of a matrix
+
+ :type input: theano.tensor.TensorType
+ :param input: Theano array or matrix to take the norm of.
+
+ """
return T.sqrt((input * input).sum(axis=0))
def normalize(vector, scale=1.0, offset=0.5):
+ """
+ Normalize (Zero and scale) a vector such that it's peak to peak
+ value is equal to 'scale', and it is centered about 'offset'.
+
+ :type vector: numpy.ndarray
+ :param vector: Vector to normalize to the given parameters.
+
+ :type scale: float
+ :param scale: Peak-to-peak range to stretch or shrink the vector's
+ current peak-to-peak range to.
+
+ :type offset: float
+ :param offset: Value at which to center the peak-to-peak range at.
+
+ """
return (vector - vector.min()) * scale / vector.ptp()
+
没关系。底部有一个迷你指南。我明白了。因此，我们希望将新函数放入此提交中，并将其他函数的文档放入另一个提交中。根据迷你文档：# To remove '+' lines, delete them.
# Manual hunk edit mode -- see bottom for a quick guide
@@ -50,13 +50,74 @@ import PIL.Image as im
import constant
+
+def exp_range(min=None, max=None, step=None):
+ """
+ Generate an exponentially increasing value scaled and offset such
+ that it covers the range (min, max]. Behaviour is similar to
+ exp(x), scaled such that the final value generated is equal to
+ 'max'. 'step' defines the granularity of the exponential
+ function. The default value is 5, corresponding to a step-size
+ of tau.
+
+ :type min: float
+ :param min: minimum value of range (offset)
+
+ :type max: float
+ :param max: Maximum (final) value of range
+
+ :type step: int
+ :param step: Number of incremental steps within the range
+ (min, max]
+
+ """
+ if min is None:
+ raise StopIteration
+
+ # One input argument (same as range(10))
+ if min is not None and max is None and step is None:
+ step = min
+ min = 0.
+ max = 1.
+ elif step is None:
+ step = 5
+
+ for i in xrange(step):
+ exp_rate = np.exp(i - (step-1))
+ yield min + (max - min) * exp_rate
+ raise StopIteration
+
+
def norm(input):
return T.sqrt((input * input).sum(axis=0))
def normalize(vector, scale=1.0, offset=0.5):
return (vector - vector.min()) * scale / vector.ptp()
这看起来不错。让我们添加那只小狗...
error: patch failed: SdA.py:50
error: SdA.py: patch does not apply
Your edited hunk does not apply. Edit again (saying "no" discards!) [y/n]?
嗯... git add --interactive “您编辑的块不适用”以及如何读取 git diff 的输出？说明我必须更新受影响的行号。为此，现在，我可以手动计数并说“嗯，我删除了 1、2、3……23 行。我之前编辑了 74 行，现在我正在编辑……嗯……希望我有一个计算器...... 51 行”（“哇，我出汗了”）
这似乎是一种过于复杂的方法。我仍然认为补丁是正确的方法，但是如果我需要手动更新目标文件中受影响的行数，我一定是做错了。有人对如何更轻松有效地做到这一点有任何建议吗？