17

假设我们有一个 SVG 转换字符串：

transform = "translate(6,5),scale(3,3)";

是否有一个光滑的正则表达式函数可以用来将其解析为可用的东西？

4

7 回答 7

21

这是一个漂亮的小代码片段，可能会为您提供所需的内容，它应该涵盖大多数情况，以防您打算解析的字符串具有不同数量的参数：

function parse (a)
{
    var b={};
    for (var i in a = a.match(/(\w+\((\-?\d+\.?\d*e?\-?\d*,?)+\))+/g))
    {
        var c = a[i].match(/[\w\.\-]+/g);
        b[c.shift()] = c;
    }
    return b;
}

运行这个

parse('translate(6,5),scale(3,3.5),a(1,1),b(2,23,-34),c(300)');

将导致：

{
    translate: [ '6', '5' ],
    scale: [ '3', '3.5' ],
    a: [ '1', '1' ],
    b: [ '2', '23', '-34' ],
    c: [ '300' ]
}
于 2013-07-24T15:25:18.623 回答
18

假设您在浏览器中运行，您还可以使用 SVG DOM 来解析和解码转换字符串。

var svgns = "http://www.w3.org/2000/svg";

function getTransformList(transformStr)
{
  // Create a fake <rect> element to set the transform to
  var rect = document.createElementNS(svgns, "rect");
  rect.setAttribute("transform", transformStr);
  // Use the DOM to get the list of decoded transforms
  dumpTransform(rect.transform.baseVal);
}

function dumpTransform(transformList)
{
  for (var i = 0; i < transformList.numberOfItems; i++)
  {
    var transform = transformList.getItem(i);
    var m = transform.matrix;
    switch (transform.type)
    {
      case 2:
        console.log("translate("+m.e+","+m.f+")");
        break;
      case 3:
        console.log("scale("+m.a+","+m.d+")");
        break;
      case 4:
        console.log("rotate("+transform.angle+")");
        // TODO need to also handle rotate(angle, x, y) form
        break;
      case 5:
        // TODO skewX()
        break;
      case 6:
        // TODO skewY(()
        break;
      case 1:
      default:
        console.log("matrix("+m.a+","+m.b+","+m.c+","+m.d+","+m.e+","+m.f+")");
        break;
    }
  }
}

getTransformList("translate(6,5),scale(3,3)");

于 2016-12-12T13:40:49.880 回答
4

改编自@chernjie 的解决方案：

function parse_transform(a) {
    var b = {};
    for (var i in a = a.match(/(\w+)\(([^,)]+),?([^)]+)?\)/gi)) {
        var c = a[i].match(/[\w\.\-]+/g);
        b[c.shift()] = c;
    }
    return b;
}
于 2016-12-12T12:47:17.150 回答
2 
var transform = "translate(6,5),scale(3,3)";
var translate  = /translate\(\s*([^\s,)]+)[ ,]([^\s,)]+)/.exec(transform);
var translateX = translate[1]
var translateY = translate[2]
var scale  = /scale\(\s*([^\s,)]+)[ ,]([^\s,)]+)/.exec(transform);
var scaleX = translate[1]
var scaleY = translate[2]

transformValues = {translate:{x:translateX,y:translateY},
scale:{x:scaleX,y:scaleY}}

很恶心，但@icedwater 让我自己做所有的工作，所以......

于 2013-07-24T02:38:52.383 回答
0

我将对此进行尝试，并说您希望将其解析为 JSON 对象，其中包含作为列表中的条目的每个属性。这是我到目前为止最接近的：

function listIntoJSON(theTransformInQuestion) {

    // let's work with transform = "translate(6,5),scale(3,3)" as specified.
    var result = [];  // empty list to be returned
    var splitList = theTransformInQuestion.split(/\W/);
    // now splitList is ["translate", "6", "5", "", "scale", "3", "3", ""]

    for (var t = 0; t < splitList.length; t += 4) {
        var op  = {};
        op.name = splitList[t];
        op.x    = splitList[t + 1];
        op.y    = splitList[t + 2];
        result.push(op);  // add op to the result list
    }
    return result;
}

这将采取

transform = "translate(6,5),scale(3,3)";

并返回

[
    {name: "translate", x: "6", y: "5"}, 
    {name: "scale", x: "3", y: "3"}
]

并且应该适用于任意数量的转换。有点hack，但现在可以了。

于 2013-07-24T02:43:26.583 回答
0

这不是正则表达式，但有一个类似的问题（在 D3 v4 中替换 d3.transform）有一个非常好的、全面的解决方案：

function getTransformation(transform) {
  // Create a dummy g for calculation purposes only. This will never
  // be appended to the DOM and will be discarded once this function 
  // returns.
  var g = document.createElementNS("http://www.w3.org/2000/svg", "g");
  
  // Set the transform attribute to the provided string value.
  g.setAttributeNS(null, "transform", transform);
  
  // consolidate the SVGTransformList containing all transformations
  // to a single SVGTransform of type SVG_TRANSFORM_MATRIX and get
  // its SVGMatrix. 
  var matrix = g.transform.baseVal.consolidate().matrix;
  
  // Below calculations are taken and adapted from the private function
  // transform/decompose.js of D3's module d3-interpolate.
  var {a, b, c, d, e, f} = matrix;   // ES6, if this doesn't work, use below assignment
  // var a=matrix.a, b=matrix.b, c=matrix.c, d=matrix.d, e=matrix.e, f=matrix.f; // ES5
  var scaleX, scaleY, skewX;
  if (scaleX = Math.sqrt(a * a + b * b)) a /= scaleX, b /= scaleX;
  if (skewX = a * c + b * d) c -= a * skewX, d -= b * skewX;
  if (scaleY = Math.sqrt(c * c + d * d)) c /= scaleY, d /= scaleY, skewX /= scaleY;
  if (a * d < b * c) a = -a, b = -b, skewX = -skewX, scaleX = -scaleX;
  return {
    translateX: e,
    translateY: f,
    rotate: Math.atan2(b, a) * 180 / Math.PI,
    skewX: Math.atan(skewX) * 180 / Math.PI,
    scaleX: scaleX,
    scaleY: scaleY
  };
}

console.log(getTransformation("translate(20,30)"));  
console.log(getTransformation("rotate(45) skewX(20) translate(20,30) translate(-5,40)"));

于 2021-10-21T14:22:33.820 回答
0

即使这是一个老问题，今天我也有同样的需求，最终得到了这个正则表达式：

const regex = /((\w+)\((,?\s*-?\d*\.?\d+(px|in|px|cm|mm|pt|pc|em|ex|ch|rem|deg|rad|grad|turn)?)+\)\s*)/gi;

很长，但它也考虑了计量单位。

你可以在这里测试它：https ://regex101.com/r/M8rRjo/1/

于 2020-11-13T11:44:27.403 回答